B generate ideas not 100 percent positive though
Answer:
0.0757 kg
Explanation:
m = mass of the body = 95 kg = 95000 g
ΔT = change in the temperature of the body = 0.45 °C
c = specific heat capacity of the body = 4.0 J/(g °C)
M = mass of water evaporated
L = latent heat of vaporization of water = 2260 J/g
Using conservation of heat
Heat gained by water = heat lost by body
ML = m c ΔT
M (2260) = (95000) (4.0) (0.45)
M = 75.7 g
M = 0.0757 kg
Answer:8.8983N
Explanation:
Horizontal component=9xcos19
Horizontal component=9x0.9887
Horizontal component=8.8983N
Answer:
5069.04 seconds
Explanation:
The parameter we are looking for is called the Orbital period of the Hubble Space Telescope.
It is given as:
where r = radius of orbit of Hubble Space Telescope
G = gravitational constant = 
M = Mass of earth
We are given that:
r = radius of the earth + distance of HST from earth
r = 
M = 
Therefore, T will be:
The orbital period of the Hubble Space Telescope is 5069.04 seconds.
The most essential while choosing the privilege PFD for a traveler is the information required for choosing right PFD for the traveler's body weight and trunk size.Note that the offspring of what age under 8 years old are required to wear legitimately secured PFD while on vessel unless in securely closed cabin.
