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3 years ago

A dead organism is the same as a nonliving thing in science. Fact: Evidence:

Physics

1 answer:

nikitadnepr [17]3 years ago

4 0

No that is false

Because its a organism. Which means at one point it was a live. It just died. You cant die if you were never alive. So that means that at one time was living.

But nonliving thing in science is like a piece of plastic cant breath eat die non living

If this was helpful pls mark be as brainliest!!!!!!!!

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From the top of the engineering building, you throw a ball vertically upward. the ball strikes the ground 4.00 s later. the engi

anastassius [24]

Equations of the vertical launch:

Vf = Vo - gt

y = yo + Vo*t - gt^2 / 2

Here yo = 35.0m
Vo is unknown
y final = 0
t = 4.00 s
and I will approximate g to 10m/s^2

=> 0 = 35.0 + Vo * 4 - 5 * (4.00)^2 => Vo = [-35 + 5*16] / 4 = - 45 / 4 = -11.25 m/s

The negative sign is due to the fact that the initial velocity is upwards and we assumed that the direction downwards was positive when used g = 10m/s^2.

Answer: 11.25 m/s

5 0

3 years ago

Read 2 more answers

Jonathan must lift a 3000n rock using a lever. jonathan uses 300n of force to push down on the lever to move the rock. what is t

-Dominant- [34]

The load is the weight of the rock that Jonathan lifts:
$L=3000 N$
The effort instead is the force applied in input to the lever in order to lift the rock:
$E=300 N$

So, the ratio between load and effort for this exercise is
$\frac{L}{E}= \frac{3000 N}{300 N}=10$
So, the ratio is 10:1.

3 0

2 years ago

A small glass bead has been charged to +20 nC. A small metal ball bearing 1.0 cm above the bead feels a 0.018 N downward electri

Alla [95]

Answer:

$q=1\times10^{-8}C$

Explanation:

Let the charge on the ball bearing is q.

charge on glass bead, Q = 20 nC = 20 x 10^-9 C

Force between them, F = 0.018 N

Distance between them, d = 1 cm = 0.01 m

By use of Coulomb's law in electrostatics

$F=\frac{KQq}{d^{2}}$

By substituting the values

$0.018=\frac{9\times10^{9}\times20\times10^{-9}q}{0.01^{2}}$

$q=1\times10^{-8}C$

Thus, the charge on the ball bearing is $q=1\times10^{-8}C$

7 0

2 years ago

An object of mass m = 5.0 kg hangs from a cord around a light pulley: The length of the cord between the oscillator and the pull

puteri [66]

Answer:

$\mu=0.0049Kg/m$

Explanation:

When a standing wave is formed with six loops means the normal mode of the wave is n=6, the frequency of the normal mode is given by the expression:

$f_n=\frac{nv}{2L}$

Where $L$ is the length of the string and $v$ the velocity of propagation. Use this expression to find the value of $v$ .

$f_6=\frac{6v}{2L}\\(150)=\frac{6v}{2(2)} \\150=\frac{3v}{2} \\3v=150(2)\\ v=\frac{300}{3} \\v=100m/s$

The velocity of propagation is given by the expression:

$v=\sqrt{\frac{T}{\mu }$

Where $\mu$ is the desirable variable of the problem, the linear mass density, and $T$ is the tension of the cord. The tension is equal to the weight of the mass hanging from the cord: