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dalvyx [7]
3 years ago
7

Biologists have noticed that the chirping of crickets of a certain species is related to temperature, and the relationship appea

rs to be very nearly linear. A cricket produces 113 chirps per minute at 73 degrees Fahrenheit and 172 chirps per minute at 87 degrees Fahrenheit.Find a linear equation that models the temperature T as a function of the number of chirps per minute N.T(N)= ?
Mathematics
1 answer:
lilavasa [31]3 years ago
5 0

Answer:

T(N) = \dfrac{14N}{59} + \dfrac{2725}{59}

Step-by-step explanation:

We are given the following in the question:

The relation between  chirping of crickets and temperature is a linear function.

T(N) = aN + b

where and b are constants. T(N) is the the temperature in Fahrenheit and N is the number of chirps per minute.

"A cricket produces 113 chirps per minute at 73 degrees Fahrenheit"

73 = 113a+b

"A cricket produces 172 chirps per minute at 87 degrees Fahrenheit"

87 = 172a+b

Solving the two equations, we get,

87-73 = 172a - 113a\\14 = 59a\\\\a  =\dfrac{14}{59}\\\\73 = 113(\dfrac{14}{59}) + b\\\\b = 73 - 113(\dfrac{14}{59})\\\\b = \dfrac{2725}{59}        

Thus, the required linear function is:

T(N) = \dfrac{14N}{59} + \dfrac{2725}{59}

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zmey [24]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a i

P(X  < 185 ) =  0.3085

a ii

P(X  > 195 ) =  0.3085

a iii

P(185 < X <  195 ) = 0.3829

b

x =  208.8

Step-by-step explanation:

From the question we are told that  

   The mean is  \mu =  190

   The standard deviation is  \sigma  =  10

   

Generally the probability is  less than 185  is mathematically represented as

      P(X  < 185 ) =  P(\frac{X - \mu }{\sigma } < \frac{185 - 190 }{10 }   )

Generally \frac{X - \mu }{\sigma } = Z (The  \ standardized \  value  \  \ of  \  X)

=>   P(X  < 185 ) =  P(Z< -0.5)

From the z-table the p value  of  (Z< -0.5) is

    P(Z< -0.5) = 0.3085

So

    P(X  < 185 ) =  0.3085

Generally the probability is  less than 185  is mathematically represented as

      P(X > 195 ) =  P(\frac{X - \mu }{\sigma } > \frac{195 - 190 }{10 }   )

=>   P(X  >  195 ) =  P(Z > 0.5)

From the z-table the p value  of  (Z > 0.5) is

    P(Z > 0.5) = 0.3085

So

    P(X  > 195 ) =  0.3085

Generally the probability is  less than 185  is mathematically represented as

      P(185 < X <  195 ) =  P( \frac{185 - 190 }{10 } <  \frac{X - \mu }{\sigma } <  \frac{195 - 190 }{10 } )

=>   P(185 < X <  195 ) =  P(-0.5 < Z > 0.5)

=>   P(185 < X <  195 ) = P(Z  <  0.5 ) -  P(Z <  -0.5)

From the z-table the p value  (Z <  0.5) and  (Z <  -0.5) is  

    P(Z < 0.5) =  0.6915

and  

   P(Z < - 0.5) = 0.3085

So

=>   P(185 < X <  195 ) = 0.6915 -  0.3085

=>   P(185 < X <  195 ) = 0.3829

Generally the level of cholesterol the 97th percentile represents  is mathematically evaluated as

    P(X < x ) =  0.97

=> P(X < x ) = P(\frac{X - \mu}{\sigma }  <  \frac{x - 190}{10 }  ) = 0.97

=>   P(X < x ) = P(Z <  \frac{x - 190}{10 }  ) = 0.97

From the z-table  the z-score for  0.97  is  

      z-score =  1.88

=>

  \frac{x - 190}{10 } =  1.88

=>x =  208.8

7 0
3 years ago
NEED HELP ASAPP PLEASEE
mart [117]

Answer:

22.25

Step-by-step explanation:

take the two values away

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5 0
2 years ago
Find the area of each figure.<br> 10 mm<br> 15 mm<br> B mm<br> 30 mm
guapka [62]

Answer:370mm^3

Step-by-step explanation:

You would first find the area of the whole rectangle without the hole, so (15)(30)=450

Next find the area of the hole, (8)(10)=80

To find the area you must subtract the area of the hole from the rectangle.

450-80=370

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2 years ago
Gulf gully and jump rope road are a pretty far distance.If the scale for the map is 0.5 inches=2.3 miles,what is the actual dist
Nezavi [6.7K]

Answer:

12 cm = 21.62 miles

6 cm = 11.04 miles

Step-by-step explanation:

To find the distance, set up a proportion. A proportion is two equal ratios set equal to each other. We form the ratios by using corresponding values. We write a ratio of \frac{map}{real world} and simplify.

We know \frac{map}{real world}=\frac{0.5in}{2.3 miles}. We know the distance on the map is 12 cm and 6 cm whish converts to 4.7 inches and 2.4 inches. We can write \frac{4.7in}{xmiles} and  \frac{2.4in}{xmiles}

We set them equal.

\frac{0.5}{2.3}=\frac{4.7}{x}

and

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To solve each proportion, we'll cross multiply by multiplying numerator with denominator across the equal sign.

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and

2.3(2.4)=0.5(x)\\5.52=0.5x\\\frac{5.52}{0.5}=\frac{0.5x}{0.5} \\11.04 miles=x

8 0
3 years ago
I need help with this pls ASAP
Andrei [34K]
K is the right answer for the problem!
6 0
3 years ago
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