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Kobotan [32]
3 years ago
14

Which metal in Period 5 is very reactive and has two valence electrons in each atom? rubidium (Rb) strontium (Sr) zirconium (Zr)

silver (Ag)
Chemistry
2 answers:
Paul [167]3 years ago
6 0

Answer:

strontium (Sr)

Explanation:

jus took the quiz

vladimir1956 [14]3 years ago
4 0
<h3>Answer:</h3>

           Strontium (Sr)

<h3>Explanation:</h3>

                        The condition given in statement is the presence of two valence electron. Hence, first we found the electronic configuration of given atoms as follow;

                       Rubidium                         [Kr] 5s¹

                      Strontium                        [Kr] 5s²

                       Zirconium                         [Kr] 4d² 5s²

                      Silver                                 [Kr] 4d¹⁰ 5s¹

From above configurations it is cleared that only Strontium and Zirconium has two electrons in its valence shell.

We also know that s-block elements are more reactive than transition elements due to less shielding effect in transition elements hence, making it difficult for transition metals to loose electrons as compared to s-block elements. Therefore, we can conclude that Strontium present in s-block with two valence electrons is the correct answer.

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A blood sample is diluted by placing 0.2ml of the blood in a tube and filling the tube to the 5ml mark with a solution. what per
MariettaO [177]
V₀=0.2 ml
v=5 mL

a=100v₀/v

a=100×0.2/5=4%

4%
6 0
3 years ago
Y = 57.15 − 0.5 X If Y equals 5 , what is X ?<br><br> Then is Y=3, what is X?
Fiesta28 [93]

When y equals 5, x is 104.3

When y equals 3 then x is 108.3

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

y = 57.15 - 0.5x

<h3><u>If y equals 5 what is x ?</u></h3>

Substitute y = 5 in given expression

5 = 57.15 - 0.5(x)

5 = 57.15 - 0.5x

0.5x = 57.15 - 5

0.5x = 52.15

Divide both sides by 0.5

x = 104.3

Thus when y equals 5, x is 104.3

<h3><u>If y = 3 what is x ?</u></h3>

Substitute y = 3 in given expression

3 = 57.15 - 0.5(x)

3 = 57.15 - 0.5x

0.5x = 57.15 - 3

0.5x = 54.15

Divide both sides by 0.5

x = 108.3

Thus when y equals 3 then x is 108.3

7 0
4 years ago
Why can't methanol, CH3OH, be used as a solvent for sodium amide, NaNH2? Sodium amide is nonpolar and methanol is polar. Sodium
Elodia [21]

Answer: sodium amide undergoes an acid -base reaction

Explanation:

sodium amide is a ionic compound and basically exists as sodium cation and amide anion. Amide anion is highly basic in nature and hence as soon as  there is amide anion generated in the solution , Due to its very pronounced acidity it very quickly abstracts the slightly acidic proton available on methanol.

This leads to formation of ammonia and sodium methoxide.

Hence sodium amide reacts with methanol and abstracts its only acidic proton and form ammonia and sodium Methoxide.

Hence the 3rd statement is a corrects statement.

So we cannot use methanol for sodium amide because sodium amide itself would react with methanol and the inherent molecular natur of sodium amide would then change.

The 1st and 2nd statements both are incorrect because both the compounds methanol as well as sodium amide have dipole moments and hence are polar molecules.

The 4th statement is also incorrect as both the molecules have dipole moment and hence there would be ion-dipole forces operating between them.

The following reaction occurs:

NaNH₂+CH₃OH→NH₃+CH₃ONa

4 0
3 years ago
Which of the following best describes an alkali?
julia-pushkina [17]

Answer:

A. Any substance with a pH above 7.

Explanation:

On the pH scale substances whose value is greater than 7 and less than 14 are termed alkali.

Acids have  a pH of less than 7 whereas neutral compounds such as water has pH of 7.

  • An alkali is any substance that produces excess hydroxyl ion in solutions.
  • Water soluble bases are known as alkali.
  • They are usually certain metallic oxides, metallic hydroxides and aqueous ammonia.
7 0
3 years ago
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