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3 years ago

13. Which contains the same number of molecules as 22.4 liters of N2 at STP?

Chemistry

1 answer:

Oksanka [162]3 years ago

7 0

Answer:

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Explanation:

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What is the mass of 8.8 x 10^22 of magnesium

Romashka-Z-Leto [24]

Answer:

0.05

moles

Explanation:

In a mole of any substance, there exist

6.02⋅1023

units of that substance.

So here, we got:

3.01⋅1022Mg atoms⋅1mol6.02⋅1023M gatoms=0.05mol

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3 years ago

How do multiple bonds affect the shape of a molecule?.

jok3333 [9.3K]

Answer:

hyprogenic

Explanation:

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3 years ago

How much work (in JJ) is required to expand the volume of a pump from 0.0 LL to 2.5 LL against an external pressure of 1.1 atmat

stira [4]

Answer:

- 278.85 J

Explanation:

Given that:

Pressure = 1.1 atm

The initial volume V₁ = 0.0 L

The final volume V₂ = 2.5 L

The work that takes place in a reaction at constant pressure can be expressed by using the equation:

W = P(V₂ - V₁ )

Since the volume of the gas is expanded from 0 to 2.5 L when 1.1 atm pressure is applied. Then, the work can be given by the expression:

W = - P(V₂ - V₁ )

W = -1.1 atm ( 2.5 - 0.0) L

W = -1.1 atm (2.5 L)

W = -2.75 atm L

Recall that:

1 atm L = 101.4 J

Therefore;

-2.75 atm L = ( -2.75 × 101.4 )J

= -278.85 J

Thus, the work required at the chemical reaction when the pressure applied is 1.1 atm = - 278.85 J

8 0

3 years ago

Is the molecule NO nonpolar covalent, polar covalent, or ionic?

dexar [7]

B. Polar Covalent, NO is not a symmetrical molecule, therefore making it Polar rather than Non-Polar.

4 0

3 years ago

Read 2 more answers

Consider an insulated container in which water (2.58 g) solidifies at 0 oC and 1 atm on the surface of a 55 g aluminum block. As

yarga [219]

Answer:

17.41°C is the change in temperature of the aluminum block.

Explanation:

Latent heat of fusion water = 334 J/g

Heat required to freeze 1 gram of water = -334 J

Heat required to freeze 2.58 grams of water = Q

$Q=2.58 g\times (-334 J/g)=-861.72 J$

Heat lost by water will be equal to heat gained by the aluminum block

$Q'=-Q$

$Q'= -(-861.72 J)=861.72 J$

Formula used to calculate heat absorbed by substance:

$Q=mc\Delta T$

Where:

Q = heat absorbed by substance

c = specific heat of substance

m = Mass of the substance

ΔT = change in temperature of the substance

We have :

Mass of aluminum block= m= 55 g

Heat capacity of aluminum = c = 0.9 J/g°C

Change in temperature of the aluminum block= ΔT = ?

Heat absorbed by the aluminum = Q'

$861.72 J=55 g\times 0.9 J/g^oC\times \Delta T$

$\Delta T=17.41 ^oC$

17.41°C is the change in temperature of the aluminum block.

8 0

3 years ago