Both dominant and recessive are orange
OO= O
Oo=O
oO=O
oo= White
Explanation:
The given data is as follows.
T = = (120 + 273.15)K = 393.15 K,
As it is given that it is an equimolar mixture of n-pentane and isopentane.
So, = 0.5 and = 0.5
According to the Antoine data, vapor pressure of two components at 393.15 K is as follows.
(393.15 K) = 9.2 bar
(393.15 K) = 10.5 bar
Hence, we will calculate the partial pressure of each component as follows.
=
= 4.6 bar
and,
=
= 5.25 bar
Therefore, the bubble pressure will be as follows.
P =
= 4.6 bar + 5.25 bar
= 9.85 bar
Now, we will calculate the vapor composition as follows.
=
= 0.467
and,
=
= 0.527
Calculate the dew point as follows.
= 0.5, = 0.5
= 0.101966
P = 9.807
Composition of the liquid phase is and its formula is as follows.
=
= 0.5329
=
= 0.467
Explanation:
The given data is as follows.
= 5.00 L, = ?
= -50.0 + 273 = 223 K, = 100.0 + 273 = 373 K
P = constant
Therefore, calculate as follows.
=
Since pressure is constant so, P will be cancelled out from both the sides.
=
=
=
=
= 8.36 L
Thus, we can conclude that is 8.36 L.
(1) gains one electron and becomes a negatively charged ion
(2) gains three electrons and becomes a negatively charged ion
<u>(3) loses one electron and becomes a positively charged ion</u>
<span>(4) loses three electrons and becomes a positively charged ion</span>