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3 years ago

15

What 4 characteristics do all animals have?

2 answers:

Setler79 [48]3 years ago

6 0

Answer:

1. Animals are multicellular.

2. Animals are heterotrophic, obtaining their energy by consuming energy-releasing food substances.

3. Animals typically reproduce sexually.

4. Animals are made up of cells that do not have cell walls.

5. Animals are capable of motion in some stage of their lives.

6. Animals are able to respond quickly to external stimuli as a result of nerve cells, muscle or contractile tissue, or both.

plz mark me as brainliest :)

Alexandra [31]3 years ago

4 0

All animals have the least four common characteristics although they are not exclusive to the Animalia kingdom, these characteristics include heterotrophic, multicellular, mobility/motility and cells without cell walls.
Hope this helps!

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A 50.0 mL graduated cylinder has a mass of 65.1 g. When it is filled with an unknown liquid to the 49.3 mL mark, the cylinder an

Delvig [45]

<u>Answer:</u> The density of liquid is $1.12g/cm^3$

<u>Explanation:</u>

We are given:

Mass of cylinder, $m_1$ = 65.1 g

Mass of liquid and cylinder combined, M = 120.5 g

Mass of liquid, $m_2$ = $(M-m_1)=(120.5-65.1)g=55.4g$

To calculate density of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

We are given:

Mass of liquid = 55.4 g

Volume of liquid = 49.3 mL = $49.3 cm^3$ (Conversion factor: $1mL=1cm^3$ )

Putting values in above equation, we get:

$\text{Density of liquid}=\frac{55.4g}{49.3cm^3}\\\\\text{Density of liquid}=1.12g/cm^3$

Hence, the density of liquid is $1.12g/cm^3$

3 0

3 years ago

Purification of copper can be achieved by electrorefining copper from an impure copper anode onto a pure copper cathode in an el

givi [52]

Answer: The amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

Explanation:

We are given:

Moles of electron = 1 mole

According to mole concept:

1 mole of an atom contains $6.022\times 10^{23}$ number of particles.

We know that:

Charge on 1 electron = $1.6\times 10^{-19}C$

Charge on 1 mole of electrons = $1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C$

$Cu^{2+}+2e^-\rightarrow Cu$

$2\times 96500=193000C$ is passed to deposit = 1 mole of copper

63.5 g of copper is deposited by = 193000 C

$14\times 1000g=14000g$ of copper is deposited by = $\frac{193000}{63.5}\times 14000=42551181 C$

To calculate the time required, we use the equation:

$I=\frac{q}{t}$

where,

I = current passed = 40.0 A

q = total charge = 42551181 C

t = time required = ?

Putting values in above equation, we get:

$40.0=\frac{42551181 C}{t}\\\\t=1063779sec$

Converting this into hours, we use the conversion factor:

1 hr = 3600 seconds

So, $1063779s\times \frac{1hr}{3600s}=295hr$

Hence, the amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

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4 years ago

If 16.9 kg of Al2O3(s), 57.4 kg of NaOH(l), and 57.4 kg of HF(g) react completely, how many kilograms of cryolite will be produc

hodyreva [135]

Answer: 69.72 kg of cryolite will be produced.

Explanation:

The balanced chemical equation is:

$Al_2O_3(s)+6NaOH(l)+12HF(g)\rightarrow 2Na_3AlF_6+9H_2O$

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

moles of $Al_2O_3$ = $\frac{16.9\times 1000g}{102g/mol}=165.7moles$

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As 1 mole of $Al_2O_3$ reacts with 6 moles of $NaOH$

166 moles of $Al_2O_3$ reacts with = $\frac{6}{1}\times 166=996$ moles of $NaOH$

As 1 mole of $Al_2O_3$ reacts with 12 moles of $HF$

166 moles of $Al_2O_3$ reacts with = $\frac{12}{1}\times 166=1992$ moles of $HF$

Thus $Al_2O_3$ is the limiting reagent.

As 1 mole of $Al_2O_3$ produces = 2 moles of cryolite

166 moles of $Al_2O_3$ reacts with = $\frac{2}{1}\times 166=332$ moles of cryolite

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Thus 69.72 kg of cryolite will be produced.

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All of the following methods would increase the solubility of a solid solute, except for

cricket20 [7]

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Answer:

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3 years ago

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