Answer:
Option (3) 334J.
Explanation:
The following data were obtained from the question:
Mass (m) = 1g
Heat of fusion (ΔHf) = 334J/g
Heat (Q) =?
The heat released can be obtained as follow:
Q = m·ΔHf
Q = 1 x 334
Q = 334J.
Therefore, the heat released when 1g is converted to ice is 334J.
Answer:
The maximum amount of work that can be done by this system is -2.71 kJ/mol
Explanation:
Maximum amount of work denoted change in gibbs free energy during the reaction.
Equilibrium concentration of B = 0.357 M
So equilibrium concentration of A = (1-0.357) M = 0.643 M
So equilibrium constant at 253 K,
[A] and [B] represent equilibrium concentrations
When concentration of A = 0.867 M then B = (1-0.867) M = 0.133 M
So reaction quotient at this situation,
We know,
where R is gas constant and T is temperature in kelvin
Here R is 8.314 J/(mol.K), T is 253 K, Q is 0.153 and is 0.555
So,
= -2710 J/mol
= -2.71 kJ/mol
Answer:
Iron (II) oxide
Explanation:
Chemical formula of the given compound = FeO
The given compound is an oxide.
In oxides, oxidation state of 'O' is -2.
Let oxidation state of Fe be x. It is a neutral compound.
Therefore, x - 2 = 0
x = +2
So, the oxidation state of Fe in FeO = +2
In the nomenclature of inorganic compounds, cation is named first. After that oxidation state of cation is written. Name of anion is written after that.
Cation = Iron
Anion = oxide
So the name of the given compound would be Iron (II) oxide.