All categories

3 years ago

How many grams are in 1.183 mol of carbon dioxide (CO2) gas?

2 answers:

5 0

We have to convert moles to mass of carbon dioxide. We use the molar mass of carbon dioxide to convert moles to mass of $CO_{2}$

Finding out the molar mass of $CO_{2}$ :

$(1 * Molar mass of C) + (2 *Molar mass of O)$

$(1 * 12 \frac{g}{mol}) + (2 * 16 \frac{g}{mol}) = 44 \frac{g}{mol}$

Converting 1.183 mol carbon dioxide to mass (g):

$1.183 mol CO_{2} * \frac{44 g CO_{2}}{1 mol CO_{2}} = 52.05 g CO_{2}$

nirvana33 [79]3 years ago

3 0

Hello

the answer is 52.063238500000004

Have a nice day

You might be interested in

What enzyme is coded for in the chromosome of bacteria?

Mariulka [41]

The correct answer would be, "<span>D. beta-galactosidase".
As all the others are made in different organisms.

Hoped I helped.</span>

3 0

3 years ago

Read 2 more answers

I would like some assistance

charle [14.2K]

Answer:

#2.

Explanation:

Look at the charges. Both are positive, therefore both are cations.

6 0

2 years ago

.500 mol of br2 and .500 mol of cl2 are placed in a .500L flask and allowed to reach equilibrium. at equilibrium the flask was f

Tasya [4]

Answer : The value of $K_c$ for the given reaction is, 0.36

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

The given equilibrium reaction is,

$Br_2(aq)+Cl_2(aq)\rightleftharpoons 2BrCl(aq)$

The expression of $K_c$ will be,

$K_c=\frac{[BrCl]^2}{[Br_2][Cl_2]}$

First we have to calculate the concentration of $Br_2,Cl_2\text{ and }BrCl$ .

$\text{Concentration of }Br_2=\frac{Moles}{Volume}=\frac{0.500mol}{0.500L}=1M$

$\text{Concentration of }Cl_2=\frac{Moles}{Volume}=\frac{0.500mol}{0.500L}=1M$

$\text{Concentration of }BrCl=\frac{Moles}{Volume}=\frac{0.300mol}{0.500L}=0.6M$

Now we have to calculate the value of $K_c$ for the given reaction.

$K_c=\frac{[BrCl]^2}{[Br_2][Cl_2]}$

$K_c=\frac{(0.6)^2}{(1)\times (1)}$

$K_c=0.36$

Therefore, the value of $K_c$ for the given reaction is, 0.36

6 0

3 years ago

Read 2 more answers

A substance can change into a new kind of molecule when:

Artyom0805 [142]

Answer:

Chemical changes cause a substance to change into an entire substance with a new chemical formula. Chemical changes are also known as chemical reactions. The “ingredients” of a reaction are called reactants, and the results are called products.

Hope it helps

4 0

3 years ago

21 Which process is used to determine the concentration of an acid?

Inessa05 [86]

Answer:

4) Titration

Explanation:

Titration is a common process used to determine the concentration of acids. It does this by adding a solution of base with a known concentration to the acid until it reaches neutralization.

8 0

3 years ago