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iren [92.7K]
4 years ago
9

The product of two natural numbers is 1000. None of them is divisible by 10. Find their sum.

Mathematics
1 answer:
daser333 [38]4 years ago
5 0

Two numbers make up the factors of 1000. <span>In order that neither of the numbers be divisible by ten, each must contain powers of only one of the prime factors of 10, namely, 2 OR 5.</span>

So let's see what we can cook up. The obvious answer is

1000 = 10 * 10 * 10

1000 = 2*5 * 2*5 * 2*5

1000 = 2^3 * 5^3

1000 = 8 * 125 Are there any others?


I don't think so. The answer then comes to 8 + 125 = 133


You might argue that -8 * - 125 would also work. But the question says natural numbers not integers.

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labwork [276]

Answer:

a) P(X>8)=P(\frac{X-\mu}{\sigma}>\frac{8-\mu}{\sigma})=P(Z>\frac{8-7.6}{0.4})=P(Z>1)

And we can find this probability using the complement rule and the standard normal table or excel:

P(Z>1)=1-P(Z

b)P(X

And we can find this probability using the standard normal table or excel:

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N = 868*0.159= 138.012 \approx 138

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the amount of soft frink of a population, and for this case we know the distribution for X is given by:

X \sim N(7.6,0.4)  

Where \mu=7.6 and \sigma=0.4

We are interested on this probability

P(X>8)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>8)=P(\frac{X-\mu}{\sigma}>\frac{8-\mu}{\sigma})=P(Z>\frac{8-7.6}{0.4})=P(Z>1)

And we can find this probability using the complement rule and the standard normal table or excel:

P(Z>1)=1-P(Z

Part b

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using the standard normal table or excel:

P(Z

Part c

For this case we have a total of 868 cups and we know that the fraction of cups that will be overflow is 0.159, so then the expected number of cups overflow would be:

N = 868*0.159= 138.012 \approx 138

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Answer:

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The answer to your question is below

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