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Effectus [21]
3 years ago
12

(30 points) Air at 500 kPa and 400 K enters an adiabatic nozzle at a velocity of 30 m/s and leaves at 300 kPa and 350 K. Using v

ariable specific heats, determine (a) the isentropic efficiency, (b) the exit velocity, and (c) the entropy generation.

Physics
1 answer:
Sophie [7]3 years ago
8 0

Answer:

Explanation:

Check attachment for solution

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What is the acceleration of the block down the incline if the angle of the incline is 38 ◦ ? Answer in units of m/s 2 .
liberstina [14]
I think this is78 ms
6 0
3 years ago
B. Study the given figure and calculate the area of the leaf
yanalaym [24]

Answer:

19 cm sq

Explanation:

you have to count one full and half area occupied by leaf in each box, then you have to multiply with 1 cm sq.

4 0
3 years ago
If the temperature at the surface of Earth (at sea level) is 100°F, what is the temperature at 2000 feet if the average lapse ra
oksano4ka [1.4K]

Answer:

107 °F

Explanation:

Given that

The temperature at sea level = 100°F

height ,h= 2000 feet

The average lapse rate = 3.5°F/1000 feet

Given that rise in temperature 3.5°F per 1000 feet.

1000 feet ⇒ 3.5°F

Given that 2000 feet

2000 feet ⇒ 3.5°F x 2 +100°F

2000 feet ⇒ 107 °F

Therefore the temperature will be 107 °F  .

6 0
3 years ago
Explain the types of root​
Alex_Xolod [135]

Answer:

there are two main type of root systems.

6 0
3 years ago
Read 2 more answers
An electric field of 8.20 ✕ 105 V/m is desired between two parallel plates, each of area 25.0 cm2 and separated by 2.45 mm. Ther
astraxan [27]

Answer:

q = 1.815 \times 10^{-8} C

Charge on one plate is positive in nature and on the other plate it is negative in nature.

Explanation:

E = 8.20 x 10^5 V/m, A = 25 cm^2, d = 22.45 mm

According to the Gauss's theorem in electrostatics

The electric field between the two plates

E = \frac{\sigma }{\varepsilon _{0}}

{\sigma }= E \times {\varepsilon _{0}}

{\sigma }= 8.20 \times 10^{5} \times {8.854 \times 10^{-12}

{\sigma }= 7.26 \times 10^{-6} C/m^{2}

Charge, q = surface charge density x area

q = 7.26 \times 10^{-6} \times 25 \times 10^{-4}

q = 1.815 \times 10^{-8} C

5 0
3 years ago
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