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Effectus [21]
3 years ago
12

(30 points) Air at 500 kPa and 400 K enters an adiabatic nozzle at a velocity of 30 m/s and leaves at 300 kPa and 350 K. Using v

ariable specific heats, determine (a) the isentropic efficiency, (b) the exit velocity, and (c) the entropy generation.

Physics
1 answer:
Sophie [7]3 years ago
8 0

Answer:

Explanation:

Check attachment for solution

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Sound waves travel fastest through a A) gas. B) liquid. C) solid. D) vacuum.
earnstyle [38]

Sound waves travel faster through <em>solids</em> than they do through gases or liquids.  <em>(C)  </em>They don't travel through vacuum at all.

Example:

Speed of sound in normal air . . . around 340 m/s

Speed of sound in water . . . around 1,480 m/s

Speed of sound in iron . . . around 5,120 m/s

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3 years ago
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Select the correct answer.
VLD [36.1K]

Answer:O – H

Explanation:

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2 years ago
Is it possible for one energy store to transfer into another energy store ?Explained answer
liraira [26]

Answer:

Yes

Explanation:

Energy can be transferred from one object to another or between energy stores within the same object. For example on a pool table when white ball hits another ball energy is transferred from the kinetic store of the white ball to the kinetic store of the other ball.

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3 years ago
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What is the difference between acceleration due to gravity and gravitational force?​
ollegr [7]

Answer:

Gravity.” or “Gravity causes the moon to orbit the earth.” “Acceleration due to gravity” is much more precise. It is the acceleration that an object experiences when it is dropped with no other external forces on it. ... Near the surface of the earth the acceleration due to gravity is about 9.8

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3 years ago
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Problem 5 You are playing a game where you drop a coin into a water tank and try to land it on a target. You often find this gam
Dvinal [7]

Answer:

Option D: 1.5in in front of the target

Explanation:

The object distance is y= 6in.

Because the surface is flat, the radius of curvature is infinity .

The incident index is n_i=\frac{4}{3} and the transmitted index is n_t= 1.

The single interface equation is \frac{n_i}{y}+\frac{n_t}{y^i}=\frac{n_t-n_i}{r}

Substituting the quantities given in the problem,

\frac{\frac{4}{3}}{6in}+\frac{1}{y^i}= 0

The image distance is then y^i=-\frac{18}{4}in =-4.5in

Therefore, the coin falls 1.5in in front of the target

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3 years ago
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