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Effectus [21]
3 years ago
12

(30 points) Air at 500 kPa and 400 K enters an adiabatic nozzle at a velocity of 30 m/s and leaves at 300 kPa and 350 K. Using v

ariable specific heats, determine (a) the isentropic efficiency, (b) the exit velocity, and (c) the entropy generation.

Physics
1 answer:
Sophie [7]3 years ago
8 0

Answer:

Explanation:

Check attachment for solution

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Explain solar and lunar eclipse.with diagram.​
Lunna [17]

Explanation:

<em>an </em><em>eclipse </em><em>happens </em><em>when </em><em>one </em>

<em>astronomical </em><em>body </em><em>block </em><em>light </em>

<em>from </em><em>or </em><em>to </em><em>another</em><em>,</em><em> </em><em>the </em><em>moon </em><em>moves </em><em>into</em>

<em>the </em><em>shadow </em><em>of </em><em>earth </em><em>cast </em><em>by </em><em>sun</em><em>.</em><em>.</em><em>.</em><em> </em><em>In </em><em>a </em><em>solar </em>

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4 0
3 years ago
Read 2 more answers
What is the relationship between the structure of a white blood cell and its function in the body.
mario62 [17]
White blood cell,also called leukocyte or white corpuscle,a cellular component of the blood that lacks hemoglobin,has a nucleus,is capable of motility,and defends the body against infection and disease by ingesting foreign materials and cellular debris,by destroying infectious agents and cancer cells.
6 0
3 years ago
The speed of light waves is?
denpristay [2]

Answer:

299,792,458 metres per second

Explanation:

3 0
3 years ago
A wire lying along a y axis form y=0 to y=0.25 m carries a current of 2.0 mA in the negative direction of the axis. the wire ful
il63 [147K]

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Explanation:

8 0
3 years ago
Helppp!!!!! Please!!
neonofarm [45]

Answer:

  • The impulse exerted by the ball is 7.2 kg.m/s
  • The average force exerted on the ball by the bat is 600 N.

Explanation:

Given;

mass of the baseball, m = 0.144 kg

velocity of the baseball, v₁ = 20 m/s

velocity of the batter, v₂ = -30 m/s (opposite direction to the ball's speed)

The impulse exerted by the ball is calculated as follows;

J = ΔP = mv₁ - mv₂

ΔP = m(v₁ - v₂)

ΔP = 0.144 [20 - (-30)]

ΔP = 0.144 ( 20 + 30 )

ΔP = 0.144 (50)

ΔP = 7.2 kg.m/s

The average force exerted on the ball by the bat is calculated as;

F = \frac{\Delta P }{t} \\\\where; t \ is \ time \ of \ contact= 0.012 \ s\\\\F = \frac{7.2}{0.012} \\\\F = 600 \ N

3 0
3 years ago
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