Question

For the function z=9x^3-4y^2+2xy, Find dz/dx.

Answer 1

Answer:

The value of dz/dx is 27x^2 + 2y

Step-by-step explanation:

We have to given the function z = 9x^3 - 4y^2 + 2xy and we have to find the partial derivative of the given function. In the given function, we have to find partial derivation with respect to x. Therefore, the other values will be considered as constant and during the partial derivation, the constant value will become zero.

$z=9x^3-4y^2+2xy \\\frac{dz}{dx} = 9\times 3x^{3-1} -0 +2y \\\frac{dz}{dx} =27x^2 + 2y$

Therefore, the value of dz/dx is 27x^2 + 2y