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3 years ago

What two factors determine the acceleration of an object

Chemistry

1 answer:

cestrela7 [59]3 years ago

7 0

The total mass and the force exerted on it

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if 2 grams of element x combine with 4 grams of element y to form compound xy how many grams of element y would combine with 34

geniusboy [140]

Please i need answers

8 0

3 years ago

What is the symbol for the isotope of 58co that possesses 33 neutrons?

Cerrena [4.2K]

Cobalt because it has an atomic mass of 58 and 33 neutrons.

3 0

3 years ago

What is the name of the alkane having five carbons?

Tatiana [17]

Explanation:

Alkanes are the simple hydrocarbons that have only carbon and hydrogen atoms attached to each other through single bonds.

General chemical formula of an alkane is $C_{n}H_{2n+2}$ , where n is any integer.

For example, if n = 5 then formula of the alkane will be as follows.

$C_{n}H_{2n+2}$

= $C_{5}H_{2(5)+2}$

= $C_{5}H_{12}$

A suffix "-ane" is added in the name of an alkane. So, an alkane with five carbon atoms will be known as pentane.

7 0

3 years ago

Read 2 more answers

For the following reaction, 2.45 grams of methane (CH4) are allowed to react with 27.7 grams of carbon tetrachloride . methane (

rosijanka [135]

Answer:

The limiting reactant is CH₄

26.0g of CH₂Cl₂ is the maximum amount that can be formed

4.15g CCl₄ will remain

Explanation:

The reaction of methane, CH₄, with carbon tetrachloride, CCl₄ is:

CH₄ + CCl₄ → 2CH₂Cl₂

To find the maximum mass of dichloromethane that can be determined we need to find moles of methane and carbon tetrachloride:

Moles CH₄:

2.45g * (1mol / 16.04g) = 0.153 moles

Moles CCl₄:

27.7g * (1mol / 153.82g) = 0.180 moles

That means just 0.153 moles of CCl₄ will react until CH₄ is over.

The limiting reactant is CH₄

Assuming the whole 0.153 moles will react, the moles of CH₂Cl₂ will be:

0.153 moles CH₄ * (2 moles CH₂Cl₂ / 1 mole CH₄) = 0.306 moles of CH₂Cl₂

The mass is (Molar mass dichloromethane: 84.93g/mol):

0.306 moles of CH₂Cl₂ * (84.93g / mol) = 26.0g of CH₂Cl₂

The moles of CCl₄ that remain are:

0.180 moles - 0.153 moles = 0.027 moles

In grams:

0.027 moles * (153.82g / mol) = 4.15g CCl₄

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3 years ago

What is the product of the unbalanced combustion reaction below?

timurjin [86]

Answer: A

Explanation:

6 0

3 years ago

Read 2 more answers