Average location of the Pacific and Polar Jet Streams and typical temperature and precipitation impacts during<span> the winter over North </span>America<span>.</span>
Answer:
D. 6.3 x 10-5 mol/L NaOH
Explanation:
Alizarin yellow is an indicator that is yellow when pH < 10.1. In the same way, thymol blue is blue when pH > 9
That means the pH of the solution is between 9 - 10.1
Any acid as HCl could have a pH of these.
The solution of 3.2x10⁻⁴M NaOH has a pH of:
pOH = -log[OH-] = 3.49
pH = 14-pOH = 10.51. The pH of the solution is not 10.5
Now, the solution of 6.3x10⁻⁵M NaOH has a pH:
pOH = -log[OH-] = 4.2
pH = 14-pOH = 9.8
The pH of the solution could be 9.8. Right option is:
<h3>D. 6.3 x 10-5 mol/L NaOH</h3>
Answer : The diatomic molecule of chlorine, Cl₂, is held together by a SINGLE covalent bond.
Covalent Bond :
It is type of chemical bond, which is formed by sharing of electron between atoms . The covalent bond is formed between two non metals . The valance electron are shared to form the bond . The shared electrons are known as BONDING electron pair and the electron pair which do not take part in bonding are known as NON- BONDING electron pair. Example : O₂ , H₂ , H₂O, NH₃ etc .
Formation of covalent bond in Cl₂ :
Chlorine is present in group 17 in p block , It is a non metal .
The electronic configuration of Cl is : 1s² 2s² 2p⁶ 3s² 3p⁵ .
Since the outer shell is n= 3 , which has 7 electrons in it , hence Cl has 7 valence electrons in it .
From electronic configuration , it can be seen that Cl need 1 electron to complete its octet (3s² 3p⁶ ). Hence when two Cl atoms come close they share one-one electron with each other (as shown in image ) .
Now the octet of both the atom are complete and they are in stable state together .
When both Cl atom share one e⁻ , there is a bond formed between Cl atoms . One bond consists of 2⁻ . Hence in Cl₂ SINGLE covalent bond present .
Cl + Cl -> Cl₂
Answer:
12.33 cal/sec
Explanation:
As we know,
1 Kcal = 1000 cal
So,
0.74 Kcal = X cal
Solving for X,
X = (0.74 Kcal × 1000 cal) ÷ 1 Kcal
X = 740 cal
Also we know that,
1 Minute = 60 Seconds
Therefore, in order to derive cal/sec unit replace 0.74 Kcal by 740 cal and 1 min by 60 sec in given unit as,
= 740 cal / 60 sec
= 12.33 cal/sec