Answer:
It is mentioned that the student is mixing chemicals A and B and observes the time taken for the color to change. However, in the experiment, it is noticed that the student has repeated the procedure five times and each time he or she is modifying the concentration of chemical B. Thus, it is clear that the concentration of chemical B is the independent variable in the experiment. An independent variable is illustrated as the variable, which is controlled or modified in the experiment.
Answer: -
100 mm Hg
Explanation: -
P 1 =400 mm Hg
T 1 = 63.5 C + 273 = 336.5 K
T 2 = 34.9 C + 273 = 307.9 K
ΔHvap = 39.3 KJ/mol = 39.3 x 10³ J mol⁻¹
R = 8.314 J ⁻¹K mol⁻¹
Now using the Clausius Clapeyron equation
ln (P1 / P2) = ΔHvap / R x (1 / T2 - 1 / T1)
Plugging in the values
ln (400 mm/ P₂) = (39.3 x 10³ J mol⁻¹ / 8.314 J ⁻¹K mol⁻¹) x (
- 
= 1.38
P₂ = 100 mm Hg
Answer:
<u><em></em></u>
- <u><em>2)NH</em></u><em><u>₃</u></em>
Explanation:
The answer choices of this question are:
<h2 /><h2>Solution</h2>
The key to answer this question is to realize that <em>NH₃</em> is a gas at the given temperatures.
The solutilibty of all gases always decreases when the temperature increases. Thus, the solubility of NH₃ will decrease when the temperature rises from 10ºC to 50ºC.
The reason for this behavior of gases is that the temperature and the kinetic energy of the particles are directly proportional. Thus, as the temperature incrases the kinetic energy of the particles increases.
As the kinetic energy of the molecules of gas in the liquid solution increases, their speeds also increase, meaning that more molecules will escape from the solution to the gas phase, leaving the soluton with less dissolved gas molecules.
