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Lina20 [59]
4 years ago
13

Please help thank you.

Mathematics
1 answer:
klasskru [66]4 years ago
3 0
Use the Pythagorean Theorem.
4000^2 + 17000^2 = c^2
16000000 + 289000000 = c^2
305000000 = c^2
c = 17464 miles (B)
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Math Help Please....
rodikova [14]
Let's go through the answer choices one by one:

A. False. The line segment contains more than just the endpoints

B. False. There are points in this description that extend beyond the endpoints. If this was a line instead of a segment, then choice B would be the answer

C. True. This is the answer. Though your teacher should have added "collinear" to the sentence to make it clear that the points are between M and N, and also collinear to M and N. All of these points form the line segment MN

D. False. That would be the perpendicular bisector of MN

----------------------------------------------------------------------------------------------------

So once again, the final answer is choice C
8 0
3 years ago
2.04 miles<br> 2.5 miles<br> 2.22 miles<br> 2.94 miles
kakasveta [241]

Answer:

h=2.04\ miles

Step-by-step explanation:

Let

h-----> the high of the balloon

we know that

In the right triangle of the figure

tan(63\°)=\frac{4}{h}

h=\frac{4}{tan(63\°)}

h=2.04\ miles

8 0
4 years ago
Prove:- sin^2A-cos^2B=sin^2B-cos^2A<br>​
tankabanditka [31]

Step-by-step explanation:

1: change 'sin²A' and 'cos²B' into (1-cos²A)and (1-sin²A) respectively.

2:open the brackets and put signs accordingly.

3: cancel (-1) and (+1).

4: remaining is your answer.

4 0
2 years ago
Find the unknown measures of the indicated angles.
Sever21 [200]
The angles of a triangle always equal to 180 degrees.

Knowing this, you can solve this by this equation

Angle A + Angle B + Angle C = 180

43 + 85 + Angle C = 180

Angle C = 180 - 43 - 85
Angle C = 52

4 0
3 years ago
How many 10-digit ternary strings are there that contain exactly two 0s, three 1s, and five 2s?
Svet_ta [14]

There are \dbinom{10}2 ways of picking 2 of the 10 available positions for a 0. 8 positions remain.

There are \dbinom83 ways of picking 3 of the 8 available positions for a 1. 5 positions remain, but we're filling all of them with 2s, and there's \dbinom55=1 way of doing that.

So we have

\dbinom{10}2\dbinom83\dbinom55=\dfrac{10!}{2!(10-2)!}\dfrac{8!}{3!(8-3)!}\dfrac{5!}{5!(5-5)!}=2520

The last expression has a more compact form in terms of the so-called multinomial coefficient,

\dbinom{10}{2,3,5}=\dfrac{10!}{2!3!5!}=2520

5 0
3 years ago
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