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Xelga [282]
3 years ago
5

Debbie places two shopping carts in a cart corral. She pushes the first cart, which then pushes a second cart. What force is bei

ng exerted? Debbie exerts force on the first shopping cart. The first cart exerts force on the second cart.
Physics
2 answers:
ExtremeBDS [4]3 years ago
5 0
Hey there,

Your question states: <span>Debbie places two shopping carts in a cart corral. She pushes the first cart, which then pushes a second cart. What force is being exerted? 

based by looking at this statement above about Debbie, I understand that she (pushed) Cart (A) first. And then, she exerted (Cart B) next. From the option's that are listed above, I only see two. But from my own words, not from the only (two) options above, I see that (Debbie first exerts the second cart on to the first cart). This reason would be because the first cart is already in the corral. So then she would put the second one in there, this would mean that the second one would push the other one in there. Which means that the velocity would also be in half.

I hope you grabbed my answer in there.
~Jurgen</span>
zavuch27 [327]3 years ago
3 0

When Debbie pushes the first cart she is using an applied force. An applied force is created when someone or something pushes another thing using, of course, an applied force. Now, when the second cart is being pushed by the first cart, this is also an applied force. You can tell because the first cart is being pushed using forced and this causes the second cart to be pushed using some of the force that is being transmitted to the first cart. This means the completed sentence should look something like this...


Debbie exerts applied force on the first cart. The first cart exert applied force on the second cart.



- Marlon Nunez

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svlad2 [7]

Answer:

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Let's use Newton's second law to find the friction force. In these problems the x axis is taken parallel to the plane and the y axis perpendicular to the plane

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X axis

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Let's use trigonometry to find the components of the weight

     sin θ = Wₓ / W

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We substitute

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Work is defined by

        W = F .dx

        W = F dx cos θ

The friction force is parallel to the plane in the negative direction and the displacement is positive along the plane, so the Angle is 180º and the cos θ= -1

         

        W = -fr x

        W = (F1 - mg sin θ) L

Another way to calculate is

         fr = μ N

         fr = μ W cos θ

the work is

         W = -μ  mg cos θ L

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