The initial velocity of the ball is 8.2 m/s
Explanation:
The motion of the ball is a projectile motion, which consists of two separate motions:
- A uniform motion along the horizontal direction, at constant velocity
- A uniformly accelerated motion along the vertical direction, with constant acceleration (
, acceleration of gravity)
The range of a projectile can be derived by the equation of motions along the two directions, and it is found to be:

where
v is the initial velocity of the projectile
is the angle of projection
g is the acceleration of gravity
For the ball in this problem, we have

d = 6 m is the range
Solving for v, we find the initial velocity:

Learn more about projectile motion:
brainly.com/question/8751410
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