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3 years ago

What was the only option for getting the Apollo 13 astronauts back to Earth alive?

Physics

2 answers:

Vera_Pavlovna [14]3 years ago

4 0

They got back in the Lunar Explorer Module

Cerrena [4.2K]3 years ago

3 0

Answer:

Using the Lunar Module to travel back to Earth

Explanation:

During the Apollo 13 Mission (Launched on April 11, 1970), two days in the mission on the way to the Moon, an explosion occurred in the oxygen cylinder of the Service Module due to which Lunar landing was aborted and a quick plan was devised to bring back the Astronauts alive on Earth.

The oxygen tank of service module was used to generate electrical power and provide breathable air in the command module. The command module became uninhabitable because of quick loss of oxygen in the service module. Due to this the only option was to use the Lunar Module to get back on Earth.

Lunar module was designed to support 2 Astronauts for 2 days on Moon. A lot of procedures were drafted by Mission Control, Houston so that it could support 3 astronauts for 4 days. Although the crew faced a lot of challenges and hardships during the return journey, they came back on Earth safely after going around Moon and making a record of farthest space travel by any human being. The capsule carrying the crew , splashed in South Pacific ocean on April 17, 1970.

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People who r good at physics pls help...

malfutka [58]

Answer:

Speed and velocity both measure an object’s rate of motion. However, speed is a scalar quantity, which means that it can be described with a numerical value. Velocity is a vector quantity, which depends on direction as well as magnitude. Read these definition for more information:

speed - the rate of distance traveled by a moving object over time

velocity - the rate of displacement of a moving object over time

Basically, an object’s speed tells you how fast it’s going. Its velocity tells you how fast it’s going in a certain direction. You use speed measurements in your daily life, but physicists depend on velocity measurements more frequently in their work.

Explanation:

5 0

3 years ago

The objective lens of a certain refracting telescope has a diameter of 63.5 cm. The telescope is mounted in a satellite that orb

Ostrovityanka [42]

Answer:

0.255 m

Explanation:

We are given that

Diameter=d=63.5 cm= $63.5\times 10^{-2} m$

$1 cm=10^{-2} m$

L=265 km = $265\times 1000=265000 m$

Wavelength, $\lambda=500nm=500\times 10^{-9} m$

$1nm=10^{-9} m$

We have to find the minimum distance between two objects on the ground if their images are to be resolved by this lens.

$sin\theta=1.22\frac{\lambda}{d}$

$sin\theta=\frac{1.22\times 500\times 10^{-9}}{63.5\times 10^{-2}}$

$sin\theta=\approx \theta=9.606\times 10^{-7} rad$

$\frac{y}{L}=tan\theta\approx \theta$

$y=L\theta=265000\times 9.606\times 10^{-7}=0.255 m$

5 0

3 years ago

nder process costing, costs assigned to goods sold are transferred to the Cost of Goods Sold account from the ________. A perp

Reika [66]

Answer:

Explanation:

Under process costing, costs assigned to goods sold are transferred to the Cost of Goods Sold account from the Finished goods inventory account

The simple reason can be that Earlier than they are transferred to cost of goods sold account and being sold, they are finished goods right before it. So, they are actually transferred from finished goods inventory account only.

6 0

3 years ago

Nhận xét về nét riêng trong cách thể hiện tình yêu của xuân quỳnh qua 3 khổ thTrong thí nghiệm về giao thoa sóng trên mặt nước g

WINSTONCH [101]

Answer:

sorry bro I can't understand this language so you can ask from the Wikipedia

3 0

3 years ago

A 1.0-m-tall vertical tube is filled with 20°C water. A tuning fork vibrating at 580 Hz is held just over the top of the tube as

Mademuasel [1]

Answer:

water heights of the tube are 0.851 m , 0.553 m, 0.255 m

Explanation:

given data

frequency = 580 Hz

temperature = 20°C

tube = 1 m

to find out

water heights of the tube

solution

we will apply here formula for length that is

length L = v ( 2n -1 ) / 4f

here v is velocity o sound that is 343.2 m/s

so for n = 1

L = 343.2 ( 2(1) -1 ) / 4(580) = 0.147931 m

for n = 2

L = 343.2 ( 2(2) -1 ) / 4(580) = 0.443793 m

for n = 3

L = 343.2 ( 2(3) -1 ) / 4(580) = 0.739655 m

for n = 4

L = 343.2 ( 2(4) -1 ) / 4(580) = 1.035517 m is greater than 1

and so here height is measured less than 1 m

so water heights of the tube are 1 m - 0.147931 m , 1 m - 0.443793 m, 1 m - 0.739655 m

so water heights of the tube are 0.851 m , 0.553 m, 0.255 m

3 0

3 years ago