If h and k are constants and x^2+kx+7 is equivalent to (x+1)(x+h), what is the value of k?

1 answer:

7 0

The answer is K=(xh+x+h-7)/x
First you multiply the (X+1)(X+H) and get x^2+XH+X+H

Then you set it equal to X^2+KX+7=X^2+XH+X+H

Both X^2 CANCELS then move the 7 over by subtracting it giving you

KX=XH+X+H-7
Then divide by x giving you K by itself the answer bein K=(XH+X-H-7)/X

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