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MAXImum [283]
3 years ago
7

Factor out the GCF from the terms of the polynomial –4y5 + 6y3 + 8y2 – 2y. A. –2y4 + 3y2 + 4y – 1 B. y(–4y4 + 6y2 + 8y – 2) C. 2

y(–2y4 + 3y2 + 2y) D. –2y(2y4 – 3y2 – 4y + 1)
Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
8 0

Answer:

Option D) -2y(2y^4-3y^2-4y+1) is correct

Therefore -4y^5+6y^3+8y^2-2y=-2y(2y^4-3y^2-4y+1)

Step-by-step explanation:

Given polynomial is -4y^5+6y^3+8y^2-2y

To factorise the given polynomial by taking out the common terms of the given polynomial :

  • -4y^5+6y^3+8y^2-2y
  • =2y(-2y^4+3y^2+4y-1) ( here 2y is GCF common term so taking outside the terms of the polynomial )
  • =-2y(2y^4-3y^2-4y+1) ( now taking (-) outside )

Therefore -4y^5+6y^3+8y^2-2y=-2y(2y^4-3y^2-4y+1)

Option D) -2y(2y^4-3y^2-4y+1) is correct

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