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2 years ago

Tap to zoom in plz solve

Mathematics

2 answers:

Gennadij [26K]2 years ago

6 0

The trapezoid has two parallel sides

mafiozo [28]2 years ago

6 0

This trapezoid base 1 pair of parrelel lines

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The hypotenuse of a right triangle is 7 feet long. One leg is 4 feet longer than the other. Find the lengths of the legs, Round

Andrews [41]

Answer:

Shorter leg = 2.5 ft.

Longer leg = 6.5 ft.

Step-by-step explanation:

a^2 + b^2 = c^2

Because the hypotenuse = 7 ft, a^2 + b^2 = 49

To represent the two legs, we can use x and x+4.

x^2 + (x+4)^2 = 49

Simplifying this equation using FOIL gives us 2x^2 + 8x - 33 = 0.

Then, using the quadratic formula, we find that x = 2.5.

Thus, the shorter leg is 2.5 ft. and, when 4 is added, the longer leg is 6.5 ft.

5 0

2 years ago

Part B: Which box-and-whisker plot displays<br> Mario's data?<br><br><br> Brainliest quick

Gnoma [55]

Answer:

Step-by-step explanation:

i think it's D i have the same test today

5 0

2 years ago

Read 2 more answers

In the previous part, we obtained dy dx = 3t2 − 27 −2t . Next, find the points where the tangent to the curve is horizontal. (En

mina [271]

Answer:

(27.55, 7.22), (-11.3, 3.21).

Step-by-step explanation:

When is the tangent to the curve horizontal?

The tangent curve is horizontal when the derivative is zero.

The derivative is:

$\frac{dy}{dx} = 3t^{2} - 2t - 27$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$3t^{2} - 2t - 27 = 0$

$a = 3, b = -2, c = -27$

Then

$\bigtriangleup = b^{2} - 4ac = (-2)^{2} - 4*3*(-27) = 328$

$t_{1} = \frac{-(-2) + \sqrt{328}}{2*3} = 3.35$

$t_{2} = \frac{-(-2) - \sqrt{328}}{2*3} = -2.685$

Enter your answers as a comma-separated list of ordered pairs.

We found values of t, now we have to replace in the equations for x and y.

t = 3.35

$x = t^{3} - 3t = (3.35)^{3} - 3*3.35 = 27.55$

$y = t^{2} - 4 = (3.35)^2 - 4 = 7.22$

The first point is (27.55, 7.22)

t = -2.685

$x = t^{3} - 3t = (-2.685)^3 - 3*(-2.685) = -11.3$

$y = t^{2} - 4 = (-2.685)^2 - 4 = 3.21$

The second point is (-11.3, 3.21).

8 0

2 years ago

Why do you think it's important that we always label our units on word problems

MAXImum [283]

Word problems describe a situation where something mathematical can be found out about a system. Often, it's a real-world measurement (like numbers of apples, ages of people, inches, feet, etc.) and usually have more than one object being discussed.
The answer must be expressed in specific units so the value cannot be confused with other measurements discussed in the problem.

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2 years ago

How do you do 6x-11=-2x+5

qwelly [4]

X=2 because -2x+2 Is canceled then add 2x to 6x which is 8x then add 11 to -11 that’s canceled then add 11 to 5 which is 16 then divide 16 by 8x and x =2

4 0

2 years ago