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Oliga [24]
2 years ago
13

1) Consider the two functions. Which statement is true?A) The rate of change for function A and function B are the same.B) The s

lope of function B is negative and the slope of function A is positive.C) The rate of change for function A is greater than the rate of change for function B.D) The rate of change for function B is greater than the rate of change for function A

Mathematics
1 answer:
KIM [24]2 years ago
6 0

Answer:

B.

Step-by-step explanation:

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Consider the accompanying data on breaking load (kg/25mm width) for various fabrics in both an unabraded condition and an abrade
WITCHER [35]

Answer:

The critical value for a one-tailed test with 7 degrees of freedom and level of significance α=0.01 is tc=2.998.

The test statistic (t=1.729) is below the critical value and falls within the acceptance region, so it is failed to reject the null hypothesis.

At a significance level of 0.01, there is not enough evidence to support the claim that the true difference is significantly bigger than 0.

Step-by-step explanation:

We have a matched-pair t-test for the difference.

We have the null and alternative hypothesis written as:

H_0: \mu_d=0\\\\H_a: \mu_d>0

We have n=8 pairs of data. We calculate the difference as:

d_1=U_1-A_1=36.4-28.5=7.9

Then, with this procedure we get the sample for d:

d=[7.9,\, 35,\, 5.5,\, 4.2,\, 6.7,\, -3.7,\, -0.9,\, 3.3]

The sample mean and standard deviation are:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{8}(7.9+35+5.5+. . .+3.3)\\\\\\M=\dfrac{58}{8}\\\\\\M=7.25\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{7}((7.9-7.25)^2+(35-7.25)^2+(5.5-7.25)^2+. . . +(3.3-7.25)^2)}\\\\\\s=\sqrt{\dfrac{985.08}{7}}\\\\\\s=\sqrt{140.73}=11.86\\\\\\

Now, we can perform the one-tailed hypothesis test.

The significance level is 0.01.

The sample has a size n=8.

The sample mean is M=7.25.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=11.86.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{11.86}{\sqrt{8}}=4.1931

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{7.25-0}{4.1931}=\dfrac{7.25}{4.1931}=1.729

The degrees of freedom for this sample size are:

df=n-1=8-1=7

This test is a right-tailed test, with 7 degrees of freedom and t=1.729, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t>1.729)=0.0637

As the P-value (0.0637) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

At a significance level of 0.01, there is not enough evidence to support the claim that the true difference is significantly bigger than 0.

If we use the critical value approach, the critical value for a one-tailed test with 7 degrees of freedom and level of significance α=0.01 is tc=2.998. The test statistic is below the critical value and falls within the acceptance region, so it is failed to reject the null hypothesis.

8 0
3 years ago
Which expression can be used to model the phrase "the sum of three and a number"?
NeX [460]
The sum of three and a number is 3+x
3 0
4 years ago
A soup can, shaped like a cylinder, has a diameter of 3.5 inches and a height of 5 inches. Each serving of soup is 15 cubic inch
marissa [1.9K]

Answer:

The answer to your question is Cost of a serving = $0.62

Step-by-step explanation:

Data

diameter = 3.5 in

height = 5 in

each serving = 15 in³

Cost of the can = $1.99

Process

1.- Calculate the volume of the can

Volume = πr²h

-Substitution

Volume = (3.14)(3.5/2)²(5)

-Simplification

Volume = (3.14)(3.062)(5)

-Result

Volume = 48.08 in³

2.- Use proportions and cross multiplication to find the cost of a serving.

                   48.08 in³ ---------------- $1.99

                         15  in³ ----------------  x

                          x = (15 x 1.99)/48.08

                          x = 29.85/48.08

                          x = $0.62

7 0
3 years ago
A group of middle school boys have a mean height of 167 cm and a range of 164 cm to 169 cm. A group of high school boys have a m
Alex787 [66]

Answer:

C

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
PLS HELP WILL GIVE BRAINIEST these figures are congruent
geniusboy [140]

Answer:

C

Step-by-step explanation:

Answer is C, only need to move it up and to the right through translation.

3 0
3 years ago
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