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3 years ago

4. Round off

Mathematics

2 answers:

IRISSAK [1]3 years ago

7 0

A. 4.9m
b. 10cm
c. $11.00
d. 6kg

Andrej [43]3 years ago

5 0

Answer:

Rounding off means estimating precisely

(a) 4.918 m to the nearest 0.1 m

Rounding off to 0.1 m means to estimate it to one decimal place
Now we have to check digit at second decimal place which is 1
Rule: If digit is greater or equal to 5 increase one to previous digit

So the answer will be: 4.9 m

(b) 9.71 cm to the nearest cm,

We have to round it off to nearest cm.
As the digit after decimal is greater than 5
9 will be increased by 1

So the answer will be: 10 cm

(c) $10.982 to the nearest ten cents,

We have to round it off to nearest cents
As the digit after decimal is greater than 5
10 will be increased by 1

So the answer will be: $11

(d) 6.489 kg to the nearest - kg.

We have to round it off to nearest kg
As the digit after decimal is 4 , smaller than 5
We will check on to the next digit, 8 is greater than 5
previous digit (4) will be increased by 1

So the answer will be: 6.5 kg

I hope it will help you!

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Teacher raises A school system employs teachers at

Cerrena [4.2K]

By adding a constant value to every salary amount, the measures of

central tendency are increased by the amount, while the measures of

dispersion, remains the same

The correct responses are;

(a) The shape of the data remains the same

(b) The mean and median are increased by $1,000

Reasons:

The given parameters are;

Present teachers salary = Between $38,000 and $70,000

Amount of raise given to every teacher = $1,000

Required:

Effect of the raise on the following characteristics of the data

(a) Effect on the shape of distribution

The outline shape of the distribution will the same but higher by $1,000

(b) The mean of the data is given as follows;

$\overline x = \dfrac{\sum (f_i \cdot x_i)}{\sum f_i}$

Therefore, following an increase of $1,000, we have;

$\overline x_{New} = \dfrac{\sum (f_i \cdot (x_i + 1000))}{\sum f_i} = \dfrac{\sum (f_i \cdot x_i + f_i \cdot 1000))}{\sum f_i} = \dfrac{\sum (f_i \cdot x_i)}{\sum f_i} + \dfrac{\sum (f_i \cdot 1000)}{\sum f_i}$

$\overline x_{New} = \dfrac{\sum (f_i \cdot x_i)}{\sum f_i} + \dfrac{\sum (f_i \cdot 1000)}{\sum f_i} = \dfrac{\sum (f_i \cdot x_i)}{\sum f_i} + 1000 = \overline x + 1000$

Therefore, the new mean, is equal to the initial mean increased by 1,000

Median;

Given that all salaries, $x_i$ , are increased by $1,000, the median salary, $x_{med}$ , is also increased by $1,000

Therefore;

The correct response is that the median is increased by $1,000

Where;

n = The number of teaches;

Given that, we have both a salary, $x_i$ , and the mean, $\overline x$ , increased by $1,000, we can write;

$\sigma_{new} =\sqrt{\dfrac{\sum \left ((x_i + 1000) -(\overline x + 1000)\right )^{2} }{n}} = \sqrt{\dfrac{\sum \left (x_i + 1000 -\overline x - 1000\right )^{2} }{n}}$

$\sigma_{new} = \sqrt{\dfrac{\sum \left (x_i + 1000 -\overline x - 1000\right )^{2} }{n}} = \sqrt{\dfrac{\sum \left (x_i + 1000 - 1000 - \overline x\right )^{2} }{n}}$

$\sigma_{new} = \sqrt{\dfrac{\sum \left (x_i + 1000 - 1000 - \overline x\right )^{2} }{n}} =\sqrt{\dfrac{\sum \left (x_i-\overline x \right )^{2} }{n}} = \sigma$

Therefore;

$\sigma_{new} = \sigma$ ; The standard deviation stays the same

Interquartile range;

The interquartile range, IQR = Q₃ - Q₁

New interquartile range, IQR $_{new}$ = (Q₃ + 1000) - (Q₁ + 1000) = Q₃ - Q₁ = IQR

Therefore;

The interquartile range stays the same

Learn more here:

brainly.com/question/9995782

6 0

3 years ago

CAN YOU HELP ME PLEASE

ahrayia [7]

Answer:

3.05 yards

Step-by-step explanation:

Arc length= 2π(r)(Θ/360)

given: 7 yards is diameter, 50 degrees

radius= diameter/2 = 3.5

plug in

2π(3.5)(50/360) = 3.05 yards

8 0

3 years ago

Solve the inequality 2n – 1 < 39

MatroZZZ [7]

Answer:

n < 20

Step-by-step explanation:

2n – 1 < 39

Add 1 to each side

2n – 1+1 < 39+1

2n < 40

Divide each side by 2

2n/2 < 40/2

n < 20

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inn [45]

What are you talking about

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NISA [10]

None of the households in the United States contain five children.

The majority of the households in the United States, with at least one child, contain less than three children.

If thats wrong dont go off on me

~s9154499~

~Mia for short~

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