Step-by-step explanation:
a) Line AB ll DC
b) Line GH acts as a transversal.
c) <10 ; <12 , <9 ; <11
d) <8 = 180° - 120° = <u>60</u><u>°</u><u>(</u><u>Ans</u><u>)</u>
<6 = <u>120</u><u>°</u><u>(</u><u>Ans</u><u>)</u>
<5 = <u>60</u><u>°</u><u>(</u><u>Ans</u><u>)</u>
<4 = <u>60</u><u>°</u><u>(</u><u>Ans</u><u>)</u>
<3 = <u>120</u><u>°</u><u>(</u><u>Ans</u><u>)</u>
<2 = <u>120</u><u>°</u><u>(</u><u>Ans</u><u>)</u>
<1 = <u>60</u><u>°</u><u>(</u><u>Ans</u><u>)</u>
B is definitely the answer
rs + st = rt Plug in the values
3x + 1 + 2x - 2 = 64 Combine like terms (1 and -2)
3x -1 + 2x = 64 Combine like terms (3x and 2x)
-1 + 5x = 64 Add 1 to both sides
5x = 65 Divide both sides by 5
x = 13
The time taken by the first and the second train is 1 hour 40 minutes and 1 hour 25 minutes. Then the time when the second train at Niles junction is 5:55 p.m.
<h3>What is
speed?</h3>
The distance covered by the particle or the body in an hour is called speed. It is a scalar quantity. It is the ratio of distance to time.
We know that the speed formula

A train leaves Thorn junction at 1:25 p.m. and arrives in Niles at 3:05 p.m. the train makes two stops along the route for a total of 15 minutes.
A second train leaves Thorn junction at 4:30 p.m. and heads to Niles.
This train does not make any stops.
Let the speed of both trains be equal.
Then the time taken by the first train will be
t₁ = 3:05 p.m. - 1:25 p.m.
t₁ = 1 hour 40 minutes
Then the time taken by the second train will be
t₂ = 1:40 - 00:15
t₂ = 1:25 = 1 hour 25 minutes
The time when the second train is at Niles junction will be
→ 4:30 p.m. + 1:25
→ 5:55 p.m.
More about the speed link is given below.
brainly.com/question/7359669
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