Answer:
241°
Step-by-step explanation:
You are given the triangle internal angle (N) at Naples = 46°, and the side opposite a = 765 km. You are given the side b = 515 km, and asked to find an angle related to the internal angle opposite (C).
By the law of sines, the internal angle (C) at Canton is ...
sin(C)/b = sin(N)/a
C = arcsin((b/a)sin(N)) = arcsin(515/765·sin(46°)) ≈ 28.964°
The bearing from Elgin to Canton will be 270° less this angle, so is about 241°.
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Comment on your answer
Apparently, you added 29° to 270°, rather than subtracting. Since the direction from Elgin to Canton is south of west, the bearing angle must be between 180° and 270°. Note that a line west from Elgin will be parallel to the line east from Canton, so you can take advantage of alternate interior angles being congruent where the Elgin-Canton line crosses those parallel east-west lines.
Answer:
Let's solve your system by elimination.
3x+4y=29;6x+5y=43
Multiply the first equation by -2,and multiply the second equation by 1.
−2(3x+4y=29)
1(6x+5y=43)
Becomes:
−6x−8y=−58
6x+5y=43
Add these equations to eliminate x:
−3y=−15
Then solve−3y=−15for y:
−3y=−15
−3y
−3
=
−15
−3
(Divide both sides by -3)
y=5
Now that we've found y let's plug it back in to solve for x.
Write down an original equation:
3x+4y=29
Substitute5foryin3x+4y=29:
3x+(4)(5)=29
3x+20=29(Simplify both sides of the equation)
3x+20+−20=29+−20(Add -20 to both sides)
3x=9
3x
3
=
9
3
(Divide both sides by 3)
x=3
Answer:
x=3 and y=5
Step-by-step explanation:
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(x+a)^4 = ^4C_0 x^4 + ^4C_1 x^{4-1} a + ^4C_2x^{4-2}a^2 + ^4C_3x^{4-3}a^3 + ^4C_4x^{4-4}a^4
= x^4 + 4x^3a + 6x^2a^2 + 4xa^3 + a^4
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Answer:
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