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Ivanshal [37]
3 years ago
10

The concentration of a salt solution in terms of mass by mass percentage is 20% and the mass of the solution is 500g determine t

he mass of solute present in the solution
Chemistry
1 answer:
marin [14]3 years ago
5 0
100 grams of solute would be present as 20% of 500 is 100
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Let’s say you have 3 UV active spots in the crude material and co-spot TLC plate. One has the same Rf value as the starting mate
Troyanec [42]

Answer:

Answer: (1R,2S) / (1S, 2R) , (1R,2R) / (1S, 2S)  

Explanation:

Sodium borohydride reduction of benzoin will give four possible stereo isomers out of which are (1R,2S) - (1S, 2R) isomers and (1R,2R) - (1S, 2S) isomers which are known as enantiomers.

In general enantiomers show single spot in the TLC as they do not show any difference in Rf value (i.e) (1R,2S) - (1S, 2R) isomers show only one spot although they are two compounds and also (1R,2R) - (1S, 2S) isomers also show one spot. That is the reason why you are observing two spots in the TLC ( of reaction mixture) other than starting materilal.

8 0
3 years ago
Read 2 more answers
A sample of methane gas has a volume of 10 l at a pressure of 1.5 atm and a temperature of 20 °c. what volume does the gas occup
a_sh-v [17]
We can use combined gas laws to solve for the volume of the gas
 \frac{PV}{T}
where P - pressure, V - volume , T - temperature and k - constant
\frac{P1V1}{T1} = \frac{P2V2}{T2}
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
T1 - temperature in Kelvin - 20 °C + 273 = 293 K
T2 - 40 °C + 273 = 313 K
substituting the values 
\frac{1.5 atm*10L}{293 K} =  \frac{0.9 atm*V}{313K}
V = 17.8 L
volume of the gas is 17.8 L 
7 0
3 years ago
3/7 of a sum is Rs.1800. Find the sum​
STatiana [176]

Answer:

the sum is Rs 4,200

Explanation:

Given that

3 by 7 of the sum is $1,800

We need to find out the sum

So,

Here we assume the sum be x

So the following equation should be made

3 ÷ 7 × x = 1800

3x = 1800 × 7

x = (1800 × 7) ÷ 3

= Rs 4,200

Hence, the sum is Rs 4,200

The same would be considered and relevant

6 0
2 years ago
Determine the molarity of a solution prepared by dissolving 0.198 g of "KHP" (C8H5O4K) in enough water to make 125 mL of solutio
rosijanka [135]

Answer:

0.007756M KHP; 0.0009695 moles NaOH reacts; 0.03488M NaOH.

Explanation:

Potassium hydrogen phthalate, KHP, is a salt used as standard to determine concentration of basic solutions as NaOH solutions.

To find molarity of the KHP solution we need to convert mass of KHP to moles and divide this in 125mL = 0.125L:

<em>Moles KHP -Molar mass: 204.22g/mol-:</em>

0.198g * (1mol / 204.22g) = 0.0009695 moles KHP

<em>Molarity:</em>

0.0009695 moles KHP / 0.125L = 0.007756M KHP

NaOH reacts with KHP as follows:

NaOH + KHP → Na⁺ + KP⁻ + H₂O

That means 1 mole of NaOH reacts per mole of KHP, that means moles of NaOH that reacts are = Moles of KHP added:

0.0009695 moles NaOH reacts

In 27.80mL = 0.02780L the NaOH was contained. Molarity is:

0.0009695 moles NaOH / 0.02780L =

0.03488M NaOH

4 0
3 years ago
Use the table of data for a decomposition reaction to answer the question Concentration (C) at T1 (g/L) C at T2 (g/L) C at T3 (g
Alex73 [517]

Based on the nature of chemical equilibrium, the system reached equilibrium first at the time T2.

<h3>What is chemical equilibrium?</h3>

Chemical equilibrium refers to the state of a reversible chemical reaction in which the rate of forward reaction for the the formation is equal to the rate of backward reaction for the formation of reactants.

In the table of the decomposition reaction given above, the system reached equilibrium first at the time T2 when the concentration of the reactant and products were the same.

Learn more about chemical equilibrium at: brainly.com/question/5081082

4 0
2 years ago
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