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kari74 [83]
4 years ago
13

PLEASE HELP WILL GIVE BRAINIEST

Chemistry
1 answer:
Ad libitum [116K]4 years ago
4 0

Answer:

The mass of 106.4L of F₂ is 180.48 g

Explanation:

To find the mass of 106.4L of gas you must know the density of it.

Density = mass / volume

Density F₂ = 1,696 kg/m³

Let's make some conversion of units

1m³ = 1000 dm³

1 dm³ = 1L

1.696 kg = 1696 g

So now the rule of three to convert the density

In 1000 dm³ there are 1696 g of mass

In 1 dm³ there are 1.696 g

Density F₂ = 1.696 g/L

Density F₂ = F₂ mass / F₂ volume

1.696 g/L = F₂ mass / 106.4 L

1.696 g/L  . 106.4L = F₂ mass

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3 years ago
Part A Add single electrons and/or electron pairs as needed to complete the electron-dot symbol for astatine, At. To return the
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Answer:

7 valence electrons

Explanation:

Astatine has the atomic number 85. Thus, its electron configuration is:

[Xe] 4f¹⁴ 5d¹⁰ 6s² 6p⁵

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4 years ago
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5 0
3 years ago
for the reaction shown compute the theoretical yield of product in moles each of the initial quantities of reactants. 2 Mn(s)+3
Y_Kistochka [10]

Answer:

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Explanation:

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4 0
4 years ago
Read 2 more answers
During a titration, the pH of an analyte solution containing HA(aq) is 3.92 and the ratio of [A–]/[HA] is 0.41. What is the Ka o
Solnce55 [7]

Answer:

Ka=4.71x10^{-4}

Explanation:

Hello there!

In this case, according to the Henderson-Hasselbach equation, it is possible to write:

pH=pKa+log(\frac{[A^-]}{[HA]} )

Next, since we are given the pH and the [A–]/[HA] ratio, we can solve for the pKa as shown below:

pKa=pH-log(\frac{[A^-]}{[HA]} )

Now, we plug in the values to obtain:

pKa=3.92-log(0.41 )\\\\pKa=3.33

Next, Ka is:

Ka=10^{-pKa}=10^{-3.33}\\\\Ka=4.71x10^{-4}

Best regards!

3 0
3 years ago
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