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kari74 [83]
4 years ago
13

PLEASE HELP WILL GIVE BRAINIEST

Chemistry
1 answer:
Ad libitum [116K]4 years ago
4 0

Answer:

The mass of 106.4L of F₂ is 180.48 g

Explanation:

To find the mass of 106.4L of gas you must know the density of it.

Density = mass / volume

Density F₂ = 1,696 kg/m³

Let's make some conversion of units

1m³ = 1000 dm³

1 dm³ = 1L

1.696 kg = 1696 g

So now the rule of three to convert the density

In 1000 dm³ there are 1696 g of mass

In 1 dm³ there are 1.696 g

Density F₂ = 1.696 g/L

Density F₂ = F₂ mass / F₂ volume

1.696 g/L = F₂ mass / 106.4 L

1.696 g/L  . 106.4L = F₂ mass

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How many grams of ethylene glycol (C2H6O2) must be added to 1.15 kg of water to produce a solution that freezes at -4.46°C?
jok3333 [9.3K]

Answer:

232.5 g C2H6O2

Explanation:

The equation you need to use here is ΔTf = i Kf m

Since pure water freezes at 0 C, your ΔTf is just 4.46 C

i = 1 (ethylene glycol is a weak electrolyte)

Kf = molal freezing constant, which for water is 1.86 C/m

m = molality = x mols C2H6O2 / 1.15 kg H2O (don't know the moles of ethylene glycol we're dissolving yet)

Than,

4.46 C = 1.86 C/m (x mol C2H6O2 / 1.15 kg H2O)

Solve for x, you should get x = 2.75 mol C2H6O2

3.75 mol C2H6O2 (62 g C2H6O2 / 1 mol C2H6O2) = 232.5 g C2H6O2

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mars1129 [50]

<u>Answer:</u> The balanced chemical equation is 2KClO_3(s)\rightarrow 2KCl(s)+3O_2(g)

<u>Explanation:</u>

A balanced chemical equation is one where all the individual atoms are equal on both sides of the reaction. It follows the law of conservation of mass.

For the given unbalanced chemical equation:

KClO_3(s)\rightarrow KCl(s)+O_2(g)

<u>On the reactant side:</u>

Atoms of K = 1

Atoms of Cl = 1

Atoms of O = 3

<u>On the product side:</u>

Atoms of K = 1

Atoms of Cl = 1

Atoms of O = 2

To balance the equation, we must balance the atoms by adding 2 infront of both KClO_3(s) and KCl(s). Also, a coefficient of 3 must be written infront of O_2(g)

For the balanced chemical equation:

2KClO_3(s)\rightarrow 2KCl(s)+3O_2(g)

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Explanation:

z=p=e

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