Answer:
0.2 A, clockwise direction
Explanation:
We are given that
Current,I=25 A
Number of turns=n=20
Magnetic field at center of r the loop=B=0
d=2 m
We have to find the direction and magnitude of current flowing in the loop.
Magnetic field due to current I

Magnetic field due to I'

a=1 m
Net magnetic is zero
Therefore, 




Where 
Direction: Clockwise
Yes it is you are doing such a great job I just needed to tell u you will pass
The equation for work (W) done by an electric field is:
W = qΔV
where q is the magnitude of the charge and ΔV is the potential difference. The question gives you W and q, so plug n' play to find ΔV:
10 = 2ΔV
ΔV = 5
Answer:
The maximum speed of the car should be 13.7 m/s
Explanation:
For the car to travel at a maximum safe speed , the frictional force acting should be maximum and at the same time should provide the necessary centripetal force.
Let 'k' (=0.3502) be the coefficient of friction and 'N' be the normal force acting on the surface.
Then ,
N = mg , where 'm' is the mass of the body and 'g'(=9.8) is the acceleration due to gravity.
∴ Maximum frictional force , f = kN = kmg
Centripetal force that should act on the car to move with maximum possible speed is -
, where 'v' is the velocity of the car and 'r'(=55m) is the radius of circular path.
Equating the 2 forces , we get -

∴ 
Substituting all the values , we get -
v = 13.7 m/s.
Answer:
The angular speed of the neutron star is 3130.5 rad/s.
Explanation:
Given that,
Initial radius
Final radius 
Density of a neutron 
Equal masses of two stars 
Suppose, If the original star rotated once in 35 days, find the angular speed of the neutron star
Time period of original star T = 35 days = 3024000 s
We need to calculate the initial angular speed of original star
Using formula of angular star

Put the value into the formula


Let the initial moment of inertia of the star is

Final moment of inertia of the star is

From the conservation of angular momentum



Put the value into the formula


Hence, The angular speed of the neutron star is 3130.5 rad/s.