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iren2701 [21]
2 years ago
14

The store buys a vase for $25. The vase sells for $55. What is the markup on the vase?

Mathematics
2 answers:
iVinArrow [24]2 years ago
8 0
55 - 25 =30 its pretty easy
Hatshy [7]2 years ago
4 0

Answer:

The answer is $30

Step-by-step explanation:

Markup refers to the amount added to the cost price of goods to cover overhead and profit.

The vase was bought for $25, then is now selling for $55

$55-$25=$30

hope this helps please mark brainliest :)

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What is the slope of (-3,-6) and (4,7)​
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Answer:

13/7

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(7-(-6))/(4-(-3))

m=(7+6)/(4+3)

m=13/7

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What's the answers to Part A and Part B?​
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3 years ago
300 T(w) = 530 - w
Semmy [17]

T(110) is used to calculate the value of T when w = 110.

<h3>Linear equation</h3>

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the rate of change (slope) and b is the y intercept.

Given the linear equation:

T(w) = 530 - w

Hence T(110) is used to calculate the value of T when w = 110.

Find out more on Linear equation at: brainly.com/question/13763238

6 0
2 years ago
Please help :(((((((((((
coldgirl [10]

Answer:

a = 9, b = 3, c = 0

Step-by-step explanation:

f(x) = (1/3)^x

a = f(-2) = (1/3)^-2= 9

b = f(-1) = (1/3)^-1 = 3

c = f(0) = (1/3)^0 = 1

whenever something is to the power of 0, the answer will always be 1

6 0
2 years ago
The cosine equation for a function that has a period of 4 straight pi and an amplitude of 8
lara [203]

Answer:

y=4sin[2(x−π2)]−6

Step-by-step explanation:

The standard form of a sine function is

y=asin[b(x−h)]+k

where

•a : is the amplitude,

•2π/b : is the period,

•h : is the phase shift, and

•k : is the vertical displacement.

We start with classic

y=sinx :

graph{(y-sin(x))(x^2+y^2-0.075)=0 [-15, 15, -11, 5]}

(The circle at (0,0) is for a point of reference.)

The amplitude of this function is

a=1 .To make the amplitude 4, we need

a to be 4 times as large, so we set

a=4

.

Our function is now

y=4sinx ,and looks like:

graph{(y-4sin(x))(x^2+y^2-0.075)=0 [-15, 15, -11, 5]}

The period of this function—the distance between repetitions—right now is

2π , with b=1

.To make the period π , we need to make the repetitions twice as frequent, so we need

b=normal period/desired period

=2π/π=2

.

Our function is now

y=4sin(2x), and looks like: graph

{(y-4sin(2x))(x^2+y^2-0.075)=0 [-15, 15, -11, 5]}

This function currently has no phase shift, since

h=0

. To induce a phace shift, we need to offset

xby the desired amount, which in this case is

π2 to the right. A phase shift right means a positive

h, so we set

h = π2

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Our function is now

y=4sin[2(x−π2)] , and looks like:graph

{(y-4sin(2(x-pi/2)))((x-pi/2)^2+y^2-0.075)=0 [-15, 15, -11, 5]}

Finally, the function currently has no vertical displacement, since

k=0

.To displace the graph 6 units down, we set

k=−6

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Our function is now

y=4sin[2(x−π2)]−6, and looks like:graph {(y-4sin(2(x-pi/2))+6)((x-pi/2)^2+(y+6)^2-0.075)=0 [-15, 15, -11, 5]}

6 0
3 years ago
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