Help please geometry

Veronica and Chad are walking down the street. Veronica walks at a speed of 5 miles per hour, and Chad walks at a speed of 4 mil

stich3 [128]

Answer:

Veronica:

d=5t

Chad:

d=4t

Step-by-step explanation

yes they do represent linear equations

4 0

3 years ago

Type the correct answer in the box. Write the standard form of the quadratic equation modeled by the points shown in the table b

White raven [17]

Y =ax² + bx +c

1) Point (0,7)

7 = a*0² +b*0 +c
c = 7
y=ax² + bx + 7

2) Point (1,4)
4=a*1² + b*1 + 7, ----> 4 = a +b + 7, ------> a+b= - 3
3) Point (2, 5)
5=a*2² + b*2 + 7, ----> 5=4a+2b +7,---> -2=4a+2b, ----> -1=2a + b

4) a+b= - 3, ----> b= -3 - a (substitute in the second equation)
2a+b= -1
2a - 3 - a = -1, ----> a - 3 = -1, a =2

5) a+b= - 3
2 + b = -3
b = -5

y=2x² - 5x + 7

8 0

2 years ago

A survey was conducted that asked 1003 people how many books they had read in the past year. Results indicated that x overbar eq

Sergio [31]

Answer:

The 99% confidence interval would be given (11.448;14.152).

Step-by-step explanation:

1) Important concepts and notation

A confidence interval for a mean "gives us a range of plausible values for the population mean. If a confidence interval does not include a particular value, we can say that it is not likely that the particular value is the true population mean"

$s=16.6$ represent the sample deviation

$\bar X=12.8$ represent the sample mean

n =1003 is the sample size selected

Confidence =99% or 0.99

$\alpha=1-0.99=0.01$ represent the significance level.

2) Solution to the problem

The confidence interval for the mean would be given by this formula

$\bar X \pm z_{\alpha/2} \frac{s}{\sqrt{n}}$

We can use a z quantile instead of t since the sample size is large enough.

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$12.8 - 2.58 \frac{16.6}{\sqrt{1003}}=11.448$

$12.8 + 2.58 \frac{16.6}{\sqrt{1003}} =14.152$

And the 99% confidence interval would be given (11.448;14.152).

We are confident that about 11 to 14 are the number of books that the people had read on the last year on average, at 1% of significance.

3 0

3 years ago

What is 3+2-8+9+8+0-6-9+8

monitta

Answer:

7

Step-by-step explanation:

First,

3+2=5

5-8=-3

-3+9=6

6+8=14

14+0=14

14-6=8

8-9=-1

-1+8=7

8 0

3 years ago

2. Match the shapes given to their correct areas.

aliina [53]

Applying the formula for each identified shape that are given, the correct areas to each shape are:

a. Square = 134.6 sq. yd

b. Circle = 452.2 sq. cm

c. Parallelogram = 40.6 sq. cm

d. Rectangle = 43.2 sq. ft

e. Trapezium = 25.7 sq. m

f. Triangle = 21.6 sq. ft

a. The shape given is a square.

Area of the square = $s^2$

Where,

s = 11.6 yd

Plug in the value of s

Area of the square = $11.6^2 = 134.6 $ yd^2$

b. The shape given is a circle.

Area of the circle = $\pi r^2$

Where,

r = 12 cm

Plug in the value of r

Area of the square = $\pi \times 12^2 = 452.2 $ cm^2$

c. The shape given is a parallelogram.

Area of the parallelogram = $bh$

Where,

b = 7 cm

h = 5.8 cm

Plug in the value of b and h

Area of the parallelogram = $7 \times 5.8 = 40.6 $ cm^2$

d. The shape given is a rectangle.

Area of the rectangle = $l \times w$

Where,

l = 8.3 ft

w = 5.2 ft

Plug in the value of l and w

Area of the rectangle = $8.3 \times 5.2 = 43.2 $ ft^2$

e. The shape given is a trapezium.

Area of the trapezium = $\frac{1}{2} (a + b) \times h$

Where,

a = 2.8 m

b = 10.4 m

h = 3.9 m

Plug in the value of a, b, and h

Area of the trapezium = $\frac{1}{2}(2.8 + 10.4) \times 3.9 = 25.7 $ m^2$

f. The shape given is a triangle. (See attachment for the shape).

Area of the triangle = $\frac{1}{2} \times b \times h$

Where,

b = 9 ft

h = 4.8 ft

Plug in the value of b, and h

Area of the triangle = $\frac{1}{2} \times 9 \times 4.8 = 21.6 $ ft^2$

Therefore, applying the formula for each identified shape that are given, the correct areas to each shape are:

a. Square = 134.6 sq. yd

b. Circle = 452.2 sq. cm

c. Parallelogram = 40.6 sq. cm

d. Rectangle = 43.2 sq. ft

e. Trapezium = 25.7 sq. m

f. Triangle = 21.6 sq. ft

Learn more here:

brainly.com/question/22560863

5 0

2 years ago