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hammer [34]
3 years ago
6

Rico can drive 3 times as fast as Pablo can ride his bike. If it takes Pablo 3 hours longer then Rico to travel 36 miles,how fas

t can Pablo ride his bicycle?
Mathematics
1 answer:
Gekata [30.6K]3 years ago
3 0

Answer:

Pablo rides his bicycle at 8MPH

Step-by-step explanation:

So, we can make this into a equation

Remember, D=S*T

So we create this type of equation:(If it is a bit complicated, sorry)

\frac{36}{x} - \frac{36}{3x}=3

What I am doing here is that I am using D/S=T, But in a formula that accounts for both of them.

So, Let's Solve!

\frac{108}{3x} -\frac{36}{3x} =3\\\frac{72}{3x} =3\\72=9x\\8=x

Sorry, If it doesn't make sense... :(

Anyways, Have a Great Day! Hope This Helps!

P.S. Stay Safe!

-ANDREW-OUT!

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Rachel prepared 24 kilograms of dough after working 6 hours. How
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Answer:

24/6= 4kg/hour

44/4=11

she prepared the kg in 11 hrs of work

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Convert the number to standard form.<br><br> 8.71 xx10^(12)
ExtremeBDS [4]

8.71 xx10^(12)

The exponent is a positive number. This means the decimal point moves to the right by  the number of the exponent.

There are two digits to the right of the decimal point, so to move the decimal 12 places, you would need to add 10 zeros.

8.71 x 10^12 becomes 8,710,000,000,000.

4 0
3 years ago
Which of these statements is true?
Talja [164]

Answer:

B all square are regular polygons

8 0
3 years ago
A company wishes to monitor the variation in the length of time it takes to process and send a bill to a customer. Seven bills w
Oksi-84 [34.3K]

Answer:

R - chart

Step-by-step explanation:

Range chart (R chart) is a control chart used for processes with two or more subgroups to determine if a process is stable or not. It monitors the mean and range of a normally distributed variable simultaneously collected at regular intervals during a given time. It is used when measuring small subgroups between two and ten at regular intervals from a process. Iy is a;so used for constant subgroups.

5 0
3 years ago
The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width
blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given  perimeter

perimeter of rectangle = 2 ( length +  width )

=> 30.8 km = 2 ( x + y )  

=>x + y = \frac{30.8}{2}

=> y = 15.4 – x             ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,  

=> length^2 + width^2 = diagonal^2

=> x^2 + y^2 = 11^2

=> x^2 + y^2 = 121

On substituting value of y from (1) in above equation we get

=> x^2 + (15.4-x)^2 = 121

=>x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x   = 121

=> 2x^2-30.8x + 237.16 -121  = 0

=> 2x^2-30.8x + 116.16 = 0

Solving above quadratic equation using quadratic formula

General form of quadratic equation is  

ax^2 +bx +c = 0

And quadratic formula for getting roots of quadratic equation is  

x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}

As equation is 2x^2-30.8x + 116.16 = 0, in our case

a = 2 ,  b = -30.8 and c = 116.16

Calculating roots of the equation we get

x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}

x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{(30.8\pm29.33)}4

x=\frac{(30.8+29.33)}{4}

x=\frac{(30.8-29.33)}{4}

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,  

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0
3 years ago
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