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Softa [21]
3 years ago
9

Monique needs to buy a baseball for $20, a soccer ball for $15, and a set of tennis balls for $12. Monique has a coupon that giv

es her a discount of x percent on a baseball. She has a second coupon that gives her a discount of y percent on a set of tennis balls. The third coupon gives her a discount of z percent on her total purchase. She cannot combine the coupon for the total purchase with the other two coupons. These expressions give both possibilities for the total cost of Monique's purchase after the coupons are applied, the variables represent the percentages as decimals. (1−x)20+(1−y)12+15 (1−z)(20+15+12) Which part of the expression represents the price of the set of tennis balls after a coupon was applied directly to them?
Mathematics
2 answers:
sveta [45]3 years ago
8 0
<span>(1−x)20+(1−y)12+15

(1−z)(20+15+12)</span>
Klio2033 [76]3 years ago
3 0

Answer:

12(1 - y) and 12(1- z).

Step-by-step explanation:

Cost of a base ball = $20

Cost of the base ball after a discount coupon of x% = $20 - x% of $20

= $20(1 - x)

Similarly cost of a tennis ball with y% discount = $12(1 - y)

And cost of soccer ball = $15

So the total cost of Monique's purchase = 20(1 - x) + 15 + 12( 1 - y)

Here 12(1 - y) represents the price of the set of tennis balls after coupon z was applied.

If other coupon of z% is applied on total purchase of Monique, then the cost will be = (10 + 15 + 12) - z% of (10 + 15 + 12)

= (10 + 15 + 12)(1 - z)

In this expression 12(1 - z) represents the cost of a pair of tennis balls after z% discount on total purchase.

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MrRa [10]

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<em> The numbers are 6, 18, and 30 </em>

Step-by-step explanation:

If the three numbers are in the ratio of 3:9:10,

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<em>Then, 3x 9x (10x+10) are the progression</em>

The common difference of an arithmetic progression (d) = T₂ - T₁ = T₃ - T₂

T₂-T₁ = T₃ - T₂ .............. Equation 1

Where T₁ = first term of the progression, T₂ = Second term of the progression, T₃ = third term of the progression

<em>Given: T₁ = 3x, T₂ = 9x, T₃ = 10x +10</em>

<em>Substituting these values into equation 1</em>

<em>9x-3x = (10x+10)-9x</em>

<em>Solving the equation above,</em>

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<em />

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\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

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