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3 years ago

8

Decrease 28 by 7% immmmmmmmmm soooooooo stuck

1 answer:

iris [78.8K]3 years ago

3 0

First, multiply 28 x 7/100
then subtract the product from 28
therefore:
28 - (7/100 x 28)

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‘write an equation of the line that passes through each pair of points’ (1,2) and (4,8)

Levart [38]

<u><em>Hi there! </em></u>

Step-by-step explanation:

$Slope=\frac{Y_2-Y_1}{X_2-X_1}=\frac{RISE}{RUN}$

$\frac{8-2}{4-1}=\frac{6}{3}=2$

<em><u>So therefore, the slope is 2.</u></em>

<em><u>Final answer is 2.</u></em>

<em><u>*The answer must have a positive sign.*</u></em>

I hope this helps you!

Have a nice day! :)

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8 0

3 years ago

A bag contains 2 red, 4 blue, and 4 yellow marbles. What is the probability of pulling a red marble, putting the marble back, an

Xelga [282]

Answer:

Red: 1/5 or 0.2 or 20% (depends if the question asked you to give the answer in fraction/decimal/percentage. Either way, it's still correct)

Black: 0

Blue: 2/5 or 0.4 or 40%

Step-by-step explanation:

In total, the bag contains 10 balls,

2 are Red = 2/10 = 1/5

There are no black marbles so you have 0 chance of pulling them out.

4 are blue = 4/10 = 2/5

7 0

2 years ago

Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

4 0

2 years ago

7 tenths times 10 is another problem that i need help on

Elza [17]

Hi there!

7 tenths times 10 is pretty easy and can be done on a calculator.
7 tenths is 0.7 in standard form.

0.7 × 10 = 7

Because if you think about it...
Tenths is like being dropped down by ten... then you multiply by ten which brings it back up to whole number seven. It may not make sense but that's what it is.

Hope this helps!

8 0

3 years ago

Lena found the greatest common factor (GCF) of 24ab2c3 and 30a2b3c2 to be 6abc2 by using these steps: Step 1: GCF of 24 and 30 i

nataly862011 [7]

It is NOT the highest power shared BUT the lowest power shared. Step 2

7 0

3 years ago