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gavmur [86]
2 years ago
9

Susanne is going to college and was informed that she will get a grant to pay for

Mathematics
1 answer:
Yakvenalex [24]2 years ago
7 0

Answer:

what are the options????

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Kim bought a hat. in California. The hat cost $15 before the 8% sales tax was applied. How much did Kim pay for the hat after ta
gizmo_the_mogwai [7]

Answer:

$16.2

Step-by-step explanation:

15 x .08 [wonder how i got .08? 8% = 0.8]

= 1.2

here's where most people mess up, they usually forget to add the tax to the original cost.

15 + 1.2=

$16.2

7 0
2 years ago
Simplify each expression
Rzqust [24]

Answer:

See below

Step-by-step explanation:

1.

-6(a + 8)

Distribute the -6.

-6a - 48

2.

4(1 + 9x)

Distribute the 4.

4 + 36x or 36x + 4

3.

6(-5n + 7)

Distribute the 6.

-30n + 42

4.

(9m + 10) * 2

Rewrite.

2(9m + 10)

Distribute the 2.

18m + 20

5.

(-4 - 3n) * -8

Rewrite.

-8(-4 - 3n)

Distribute the -8.

32 + 24n or 24n + 32

6.

8(-b - 4)

Distribute the 8.

-8b - 32

7.

(1 - 7n) * 5

Rewrite.

5(1 - 7n)

Distribute the 5.

5 - 35n or -35n + 5

8.

-6(x + 4)

Distribute the -6.

-6x - 24

9.

5(3m - 6)

Distribute the 5.

15m - 30

10.

(-6p + 7) * -4

Rewrite.

-4(-6p + 7)

Distribute the -4.

24p - 28

11.

5(b - 1)

Distribute the 5.

5b - 5

12.

(x + 9) * 5

Rewrite.

5(x + 9)

Distribute the 5.

5x + 45

5 0
3 years ago
If y=20 when x=8, whats the value of x when y=-2
lisabon 2012 [21]

Answer:

x=-4/5

Step-by-step explanation:

8/20=x/-2

simplify 8/20 into 2/5

2/5=x/-2

cross product

5*x=-2*2

5x=-4

x=-4/5

8 0
3 years ago
8^10 x 8^4 simplified write your answer as a power
boyakko [2]
Answer: 8^14

8^10 x 8^4= 8^14
6 0
3 years ago
Read 2 more answers
Find an explicit solution of the given initial-value problem. (1 + x4) dy + x(1 + 4y2) dx = 0, y(1) = 0
MissTica

Answer:

a solution is 1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

Step-by-step explanation:

for the equation

(1 + x⁴) dy + x*(1 + 4y²) dx = 0

(1 + x⁴) dy  = - x*(1 + 4y²) dx

[1/(1 + 4y²)] dy = [-x/(1 + x⁴)] dx

∫[1/(1 + 4y²)] dy = ∫[-x/(1 + x⁴)] dx

now to solve each integral

I₁= ∫[1/(1 + 4y²)] dy = 1/2 *tan⁻¹ (2*y) + C₁

I₂=  ∫[-x/(1 + x⁴)] dx

for u= x² → du=x*dx

I₂=  ∫[-x/(1 + x⁴)] dx = -∫[1/(1 + u² )] du = - tan⁻¹ (u) +C₂ =  - tan⁻¹ (x²) +C₂

then

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) +C

for y(x=1) = 0

1/2 *tan⁻¹ (2*0) = - tan⁻¹ (1²) +C

since tan⁻¹ (1²) for π/4+ π*N and tan⁻¹ (0) for  π*N , we will choose for simplicity N=0 . hen an explicit solution would be

1/2 * 0 = - π/4 + C

C= π/4

therefore

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

5 0
3 years ago
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