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gavmur [86]
3 years ago
9

Susanne is going to college and was informed that she will get a grant to pay for

Mathematics
1 answer:
Yakvenalex [24]3 years ago
7 0

Answer:

what are the options????

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A circle has a center at A (4,5), Determine the radius of the circle given two end points of the circle are B (9,5) and C (-1,5)
Anna71 [15]

ANSWER :

The center-radius form of the circle equation is in the format (x – h)2 + (y – k)2 = r2, with the center being at the point (h, k) and the radius being "r". This form of the equation is helpful, since you can easily find the center and the radius.

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3 years ago
The figure below is a square pyramid where the height of the pyramid is 2 centimeters and the volume is 24 cubic centimeters. If
Murrr4er [49]

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HIIIIIIII NMMNDKK F.

Step-by-step explanation:

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3 years ago
PLZ HELP ME ITS DUE RIGHT NOW woth 18 points
Anika [276]

Answer:

The answers to the first question are A,C,D

The answer to the second question is YZ=16

Step-by-step explanation:

(1st Question)

Since <K and <M Are equal, and both <L's are equal, KL and ML are congruent (Answer choice) because of the ASA postulate.

You need to create the following equation to find the length of KN and MN 7x-4=5x+12

(Get the "x" variable to one side)

2x-4=12

(Isolate the variable)(Remove the 4)

2x=16

(Divide the 2 by itself to remove it from the x, remember to divide both sides by 2)

x=8 (Answer Choice)

Plug in the x value into each equation

KN= 7(8)-4

KN= 56-4

KN= 52

MN= 5(8)+12

MN= 40+12

MN= 52 (Answer Choice)

MN=KN

(Second Question)

Since XWY(20) is half of XWZ(40), ZWY also equals 20.

This now proves the triangle is congruent by the AAS postulate.

Since the triangles are congruent, if XY = 16, YZ also equals 16.

8 0
3 years ago
310-(30x7)=5xk solve for k
NeX [460]

Answer K= 20/x

Step-by-step explanation:

8 0
3 years ago
Find the 52nd term of the following arithmetic sequence.<br> 3, 9, 15, 21,
Alex Ar [27]

Answer:

309

Step-by-step explanation:

a = 3, d = 6, n 52

Nth term of an Arithmetic sequence is given as:

t_n=a +(n-1)d \\  \therefore \: t_{52}=3 +(52-1) \times 6 \\ \therefore \: t_{52}=3 +51\times 6 \\  \therefore \: t_{52}=3 +306 \\   \huge \red{ \boxed{\therefore \: t_{52}=309 }}\\

4 0
3 years ago
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