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Sophie [7]
3 years ago
12

8×{[(7+4)×2]-[(11-7)×4]}

Mathematics
1 answer:
TEA [102]3 years ago
4 0
Solve in the brackets first. then the rest so...
8*{[(7+4)*2]-[(11-7)*4]}      <-- this is the starting equation
8*{[(11)*2]-[(4)*4]}       <-- here i solved the inner most brackets which was 7+4 and 11-7
8*{[22]-[16]}    <-- then i multiplied 11 by 2 to get 22 and 4 by 4 to get 16
8*{6}    <-- here i subtracted 16 from 22 to get 6
48     < and then the answer which i got by multiplying 6 and 8
**note: keep BEDMAS/BODMAS in your mind. u solve the inner most brackets first and then you move outside. 
48 is the answer
hope it helped :)
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A bivariate data set has x = 21, sx = 13, y = 55, sy = 27, and r = .88. What is the equation for the regression line of y on x?
earnstyle [38]

Answer:

c) y=16.57+1.83x

Step-by-step explanation:

Equation for regression line of y on x is given as

\hat{y}=mx+b --- (1)

where

\hat{y} = predicted value

m = slope of line

b = intercept

m and b are found as

m=r\frac{S_{y}}{S_{x}}---(2)\\\\b=\bar{y}-m\bar{x}---(3)

r = correlation coefficient = 0.88

Sx = standard deviation for independent variable x = 13

Sy = standard deviation for dependent variable y = 27

\bar{x} = mean value of independent variable x = 21

\bar{x} = mean value of dependent variable y = 55

Substituting these values in (2) and (3)

m=r\frac{S_{y}}{S_{x}}\\\\m=(0.88)\frac{27}{13}\\\\m=1.83

b=\bar{y}-m\bar{x}\\\\b=55-(1.827)(21)\\\\b=16.57

Putting these values of m and b in (1)

y=1.83x+16.57

5 0
2 years ago
Please help and show all work so I can fully understand it, thanks.
seraphim [82]

Answer:

\frac{1}{m-4}

Step-by-step explanation:

\frac{\frac{4m-5}{m^4 -7m^3 +12m^2}}{\frac{4m-5}{m^3 -3m^2}}

Factor the equation:

\frac{\frac{4m-5}{m^2(m^2 -7m+12)}}{\frac{4m-5}{m^2(m-3)}}

\frac{\frac{4m-5}{m^2(m-3)(m-4)}}{\frac{4m-5}{m^2(m-3)}}

Rewrite to suit the format of multiplying two fractions. Remember, dividing two fractions is the same as multiplying the first fraction by the reciprocal of the second. A reciprocal of a fraction is when one switches the place of the numerator and the denominator, that is, the value on top (numerator), and the value on the bottom (denominator).

\frac{4m-5}{m^2(m-3)(m-4)}*\frac{m^2(m-3)}{4m-5}

Simplify, take out common terms that are found on both the numerator and denominator

\frac{4m-5}{m^2(m-3)(m-4)}*\frac{m^2(m-3)}{4m-5}

\frac{1}{m-4}

4 0
2 years ago
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