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valentinak56 [21]
3 years ago
13

Plz help it’s urgent...

Physics
1 answer:
Sonja [21]3 years ago
4 0

Answer:

srry

Explanation:

srry

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How to find acceleration in non uniform motion. Please give two ways
Olenka [21]

<u>The two ways to  find acceleration in non uniform motion are as follows:</u>

  • By Graphs
  • By Calculus

<u>Explanation:</u>

Non-uniform acceleration comprises the most common description of motion. Acceleration refers to the rate of changes of velocity per unit time. Basically, it implies that acceleration changes during motion. This variety can be communicated either as far as position (x) or time (t).

Accordingly, non-uniform acceleration motion can be carried out in 2 ways:

  • By Calculus
  • By graphs

Calculus analysis is general and accurate, but limited to the availability of speed and acceleration expressions. It is not always possible to get the expression of motion attributes in the form "x" or "t". On the other hand, the graphic method is not accurate enough, but it can be used accurately if the graphic has the correct shapes.

The use of calculations involves differentiation and integration. Integration enables evaluation of the expression of acceleration of speed and expression of movement at a distance. Similarly, differentiation allows us to evaluate expression of speed position and expression speed to acceleration.

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Consider five atoms from the second period : lithium , beryllium , boron , carbon , and nitrogen , which of these elements has t
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Answer:

Lithium has the lowest electronegativity.

Explanation:

Electronegativity measures the tendency of an atom to attract the bonding pair of electrons. As we move left to right in a period, the number of shell remains same but the number of electron increases(negative charge increases. Hence, electronegativity also increases.

As Lithium is the left most element in this period. It has the lowest electronegativity value which is equal to 0.98.

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What does a biomass pyramid show?
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I SAVE D1K BY GIVING IT CPR

Explanation:

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A perfectly flexible cable has length L, and initially it is at rest with a length Xo of it hanging over the table edge. Neglect
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Answer:

X=X_o+\dfrac{1}{2}gt^2

Explanation:

Given that

Length = L

At initial over hanging length = Xo

Lets take the length =X after time t

The velocity of length will become V

Now by energy conservation

\dfrac{1}{2}mV^2=mg(X-X_o)

So

V=\sqrt{2g(X-X_o)}

We know that

\dfrac{dX}{dt}=V

\dfrac{dX}{dt}=\sqrt{2g(X-X_o)}

\sqrt{2g}\ dt=(X-X_o)^{-\frac{1}{2}}dX

At t= 0 ,X=Xo

So we can say that

X=X_o+\dfrac{1}{2}gt^2

So the length of cable after time t

X=X_o+\dfrac{1}{2}gt^2

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Scientists in a test lab are testing the hardness of a surface before constructing a building. Calculations indicate that the en
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It depends on what that "certain amount" is.
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