Ask question

Ask question

All categories

3 years ago

11

The section of the lever to the right of the fulcrum could be described as the?

1 answer:

ZanzabumX [31]3 years ago

6 0

Answer:

Input Force

Explanation:

You might be interested in

Who knows how to do this?

stepladder [879]

I do, and my brother and son-in-law can also solve it.

Note: V1, V2, V3, I1, I2, and I3 are not labeled in the picture, so those can't be solved for.

7 0

3 years ago

A 200 g hockey puck is launched up a metal ramp that is inclined at a 30° angle. the coefficients of static and kinetic friction

elena-14-01-66 [18.8K]

My dude, have u heard of photomatg

3 0

3 years ago

Read 2 more answers

: In heavy rushIn heavy rush-hour traffic you drive in a straight line at 12 m/s for 1.5 minutes, then you have to stop for 3.5

zhuklara [117]

Guessing you want the average speed. We can multiple each speed by the time we spent going that speed, and them all together and then divide by the total time we spent in traffic to get the average speed. We spent a total of 7.5 minutes in traffic, so average speed = (12*1.5+0*3.5+15*2.5)/7.5 = 7.4 m/s

8 0

3 years ago

A 70kg car drives through a curve with radius 50m. What is the minimum angle the road should be tilted to keep the car on the ro

worty [1.4K]

when car moves along a circular path then centripetal force for taking turn will be provided by the component of normal force

Let the road is tilted by some angle

so force equations are given as

$F_n cos\theta = mg$

$F_n sin\theta = \frac{mv^2}{R}$

now divide two equations

$tan\theta = \frac{v^2}{Rg}$

now as it is given to us that

$v = 80 km/h$

$v = 80* \frac{5}{18} = 22.2 m/s$

$R = 50 m$

now we have

$tan\theta = \frac{22.2^2}{50*9.8}$

$tan\theta = 1$

$\theta = tan^{-1}1$

$\theta = 45^0$

so it is inclined at an angle of 45 degree

8 0

3 years ago

Which device records digital signals

AnnyKZ [126]

Answer:

The answer is CD, just had the same question myself.

4 0

3 years ago

Read 2 more answers