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Gekata [30.6K]
3 years ago
9

А pressure gauge with a measurement range of 0-10 bar has a quoted inaccuracy of £1.0% f.s. (+1% of full-scale reading). (a) Wha

t is the maximum measurement error expected for this instrument? (b) What is the likely measurement error expressed as a percentage of the or reading if this pressure gauge is measuring a pressure of 1 bar?​
Physics
1 answer:
Snezhnost [94]3 years ago
3 0

Answer:

<h3>I am not able to answer this question please don't mind...</h3>

Explanation:

<h3>please marks me as brainliests...</h3>
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Electrons moving back and forth through a circuit would be
yaroslaw [1]

The particles that carry charge through wires in a circuit are mobile electrons. The electric field direction within a circuit is by definition the direction that positive test charges are pushed. Thus, these negatively charged electrons move in the direction opposite the electric field.

5 0
3 years ago
Two identical traveling waves, moving in the same direction, are out of phase by π/5.0 rad. What is the amplitude of the resulta
andreev551 [17]

Answer:

Therefore the amplitude of the resultant wave is =0.95 y_m

Explanation:

The equation of wave:

y=A sin (kx-ωt)

For wave 1:

y₁=A sin (kx-ωt) = y_{m}sin (kx-ωt)

For wave 2:

y₂=A sin (kx-ωt+Φ) = y_{m}sin (kx-ωt+Φ)

Where A= amplitude=y_m

The angular frequency \omega=\frac{2\pi}{T}

k=\frac{2\pi}{\lambda} , \lambda= wave length.

t= time

T= Time period

\phi = phase difference =  \frac{\pi}{5}

The resultant wave will be

y = y₁ + y₂

 =y_m sin (kx-ωt) + y_m sin (kx-ωt+Φ)

 =y_m {sin (kx-ωt) + sin (kx-ωt+Φ)}

 =y_m\  sin(\frac{kx-\omega t +\phi + kx-\omega t }2)\ cos(\frac{kx-\omega t  +\phi -kx+\omega t}2)

 =y_m\  sin({kx-\omega t +\frac\phi 2)\ cos(\frac{\phi }2)

=y_m\ cos(\frac{\phi }2) sin({kx-\omega t +\frac\phi 2)

Therefore the amplitude of the resultant wave is

=y_m\ cos(\frac{\phi }2)

=y_m\ cos(\frac{\pi }{10})

=0.95 y_m

6 0
4 years ago
An ideal gas in a sealed container has an initial volume of 2.50 L. At constant pressure, it is cooled to 21.00 ∘C, where its fi
goblinko [34]

<u>Answer:</u> The initial temperature of the system comes out to be 147 °C

<u>Explanation:</u>

To calculate the initial temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=2.50L\\T_1=?K\\V_2=1.75L\\T_2=25^oC=(25+273)K=294K

Putting values in above equation, we get:

\frac{2.50L}{T_1}=\frac{1.75L}{294K}\\\\T_1=420K

Converting the temperature from kelvins to degree Celsius, by using the conversion factor:

T(K)=T(^oC)+273

420=T(^oC)+273\\T(^oC)=147^oC

Hence, the initial temperature of the system comes out to be 147 °C

6 0
4 years ago
A load of 250 kg is hung by a crane's cable. The load is pulled by a horizontal force such that the cable makes a 30 angle to th
Anna [14]

Answer:

1250\sqrt{3}

Explanation:

Let's look at this in a simple manner, because it is.

The crane weights 250Kg. Okay.

Since it is hung, there is the acceleration of gravity being applied on it (10m/s²)

Since F = m * a

F = 250 * 10

F = 2500

Now we know that the downward Force is 2500N.

To find the force that is being applied on that 30° angle, we can multiply our 2500N by cos30°, which happens to be \frac{\sqrt{3}}{2}.

Therefore, the force pulling the box in the cable's direction is:

\frac{2500\sqrt{3} }{2}  = 1250\sqrt{3}

<em />

<em>If you have any questions feel free to comment.</em>

<em />

<em>Have a great one and mark brainliest if it helped, please</em>

8 0
2 years ago
A material which allows fewer electrons to travel through it has a ___?
evablogger [386]
I believe it’d have a higher resistance because if it had a lower resistance more electrons could travel threw it
4 0
3 years ago
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