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r-ruslan [8.4K]
3 years ago
11

State True or False:If the positive x-axis points to the right and the x-component of velocity is negative, the cart must be mov

ing to the left.
Physics
1 answer:
umka2103 [35]3 years ago
7 0

Answer:

True

Explanation:

Velocity is a vector, therefore it consists of two elements:

- A magnitude (also called speed), which is the ratio between the displacement of the object and the time taken

- A direction, which corresponds to the direction of motion of the object

Therefore, velocity can be describes as positive or negative, depending on the direction which has been chosen as positive. If we chose the positive x-axis as positive direction, therefore:

- if the object is moving to the right (positive x-direction), the velocity will be positive

- if the object is moving to the left (negative x-direction), the velocity will be negative

So, in this case, since the velocity of the cart is negative, it must be moving to the left.

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Amount of water to be evaporated = 1 liter = 1L*1kg/liter = 1 kg

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A stone is thrown from a cliff and lands in the sea. Air resistance is negligible. Which statement is correct whilst the stone i
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a concave mirror of radius of curvature 20cm produces an inverted image three times the size of an object placed on and perpendi
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3 years ago
Runner A is initially 5.7 km west of a flagpole and is running with a constant velocity of 8.9 km/h due east. Runner B is initia
Oksanka [162]

Answer:

B meet A 0.01 km east of flagpole

Explanation:

given data

distance A = 5.7 km  west

velocity V1 = 8.9 km/h

distance B = 4.5 km  east

velocity V2 = 7 km/h

to find out

How far runners from the flagpole, when paths cross

solution

we know A and B are 5.7 + 4.5 = 10.2 km apart

and we consider here B will run distance x km for meet

so time will be for B is

time B = distance / velocity

time B = x / 7     ...................1

and

for A distance for meet = ( 10.2 - x ) km

so time A = distance / velocity

time A = ( 10.2 - x )  / 8.9      .............2

now equating equation 1 and 2

time A = time B

x / 7  =   ( 10.2 - x )  / 8.9

x = 4.490

so distance of B run for meet is 4.490 km

so distance from the flagpole when their paths cross is 4.5 - 4.490 = 0.01 km

so B meet A 0.01 km east of flagpole

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