3 years ago

PLEASE HELP!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

solong [7]3 years ago

6 0

Answer: True

In math terms, an "image" is the result after a transformation has been applied. One or more transformations can happen here. The original figure is called the "preimage" or "before image" so to speak.

So we go from "preimage" to "image"

preimage ---> image

A maps to A'

B maps to B'

C maps to C'

D maps to D'

zzz [600]3 years ago

3 0

Answer:

The answer is true

Step-by-step explanation:

I know because i had this problem.

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The midpoint of line CD is M(-3,-7). If the coordinates of C are (-2, -10), what are the coordinates of D?

Lynna [10]

Answer:

D = (-4, -4)

Step-by-step explanation:

Given;

midpoint of line CD = M(-3, -7)

coordinate of C = (-2, -10)

The coordinate of D is calculated as follows;

C(-2, -10)---------------------M(-3, -7)--------------------D

$M = \frac{D_1 + C_1}{2} \ , \ \frac{D_2 + C_2}{2} \\\\(-3, \ -7) = \frac{D_1 + (-2)}{2} , \ \frac{D_2 + (-10)}{2} \\\\(-3, \ -7) = \frac{D_1 \ - \ 2}{2} , \ \frac{D_2 -10}{2} \\\\-3 = \frac{D_1 \ - \ 2}{2} \ \ ----(1)\\\\-7 = \frac{D_2 -10}{2} \ -----(2)\\\\From \ (1): 2(-3) = D_1\ - \ 2\\\\-6 = D_1 - 2\\\\-6 + 2 = D_1\\\\-4 = D_1\\\\From \ (2) : \ 2(-7) = D_2 - 10\\\\-14 = D_2 - 10\\\\ -14 + 10 = D_2\\\\-4 = D_2\\\\The \ coordinate \ of \ D = (D_1\ , \ D_2)\\\\D = (-4 \ , \ -4)$