Answer:
i guess 3 is the best to remove
Looking at the set, we are given 18 elements. 17 is prime; it has only two factors: 1 and 17, since 1•17=17. So, the question is really asking what is the probability the numbers 1 or 17 is chosen. As mentioned earlier, 17 is prime, so there are two possible choices: 1 and 17.
P (probability) = possible outcomes / total outcomes
It is important to note that these events are “or” events, meaning that the probability can only be determined by choosing a 1 or a 17; you can’t randomly chose a 1 and 17 at the same time. So, the formula is:
P(A or B) = P(A) + P(B)
All this is saying is that given two possible outcomes, the probability occurs independent of each event; they don’t occur at the same time.
P(1 or 17) = P(1)/18 + P(1)/18
P(1 or 17) = 2/18
Since 17 is prime, it’s two and only factors are 1 and 17. The probability of randomly choosing a 1 or 17 is 2/18, meaning that there are 2 elements in the set out of a possible 18 elements that can be randomly chosen.
2/18 simplifies to 1/9
So, your answer is 1/9
Answer:
<h2>x = 7 cm</h2>
Step-by-step explanation:
The perimeter of the given triangle:
P = (2x + 1) + (x + 2) + (3x - 9) and P = 36 cm.
Therefore we have the equation:
2x + 1 + x + 2 + 3x - 9 = 36 <em>combine like terms</em>
(2x + x + 3x) + (1 + 2 - 9) = 36
6x - 6 = 36 <em>add 6 to both sides</em>
6x = 42 <em>divide both sides by 6</em>
x = 7
Standard form is
ax + by = c
Only choice A is in that form.
