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olga_2 [115]
2 years ago
12

Find the exact value of : cos(2 arctan(4/3))

Mathematics
1 answer:
QveST [7]2 years ago
7 0
Cos(2 arctan(4/3)) = cos(2 arccos(3/5)) = cos^2(arccos(3/5)) - sin^2(arccos(3/5)) = cos^2(arccos(3/5)) - sin^2(arcsin(4/5)) = (3/5)^2 - (4/5)^2 = 9/25 - 16/25 = -7/25.
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The answer is 3(a-2)(7a-5)
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Mrs.tokalaka uses 9/10 of a can of coffe beans,each week.how many cans of beans does she use in 6 weeks? write your answer two d
Snowcat [4.5K]
9 x 6 = 54

so you can write it as
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Integrate sin²2x cos²2xdx
Masteriza [31]
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From the identities above, you have

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3 0
3 years ago
Dawn has 5\6 yard of lace. She uses 4\5 of it on a dress and the rest on a jewel box. How much does she use on the jewel box
mr_godi [17]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
PLEASE HELP!!! I don’t understand
asambeis [7]

Answer:

Step-by-step explanation:

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cos(x/2)=+ or - sqrt(1+cos(x))/sqrt(2)

I'm going to figure out the sign part first for cos(x/2)...

so x is in third quadrant which puts x between 180 and 270

if we half x, x/2 this puts us between 90 and 135 (that's the second quadrant)

cosine is negative in the second quadrant

so we know that

cos(x/2)=-sqrt(1+cos(x))/sqrt(2)

Now we need cos(x)... since we are in the third quadrant cos(x) is negative...

If you draw a reference triangle sin(x)=3/5 you should see that cos(x)=4/5 ... but again cos(x)=-4/5 since we are in the third quadrant.

So let's plug it in:

cos(x/2)=-sqrt(1+4/5)/sqrt(2)

No one likes compound fractions (mini-fractions inside bigger fractions)

Multiply top and bottom inside the square roots by 5.

cos(x/2)=-sqrt(5+4)/sqrt(10)

cos(x/2)=-sqrt(9)/sqrt(10)

cos(x/2)=-3/sqrt(10)

Rationalize the denominator

cos(x/2)=-3sqrt(10)/10

3 0
3 years ago
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