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Nataly [62]
3 years ago
14

a proton is placed next to a negatively charged object in which direction does a proton move explain why

Chemistry
2 answers:
olganol [36]3 years ago
8 0

The proton will move towards the object, since protons are positively charged.

IrinaK [193]3 years ago
8 0

the proton will move towards the object because of its positive charge.

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How many orbitals are contained in the third main energy level and in the fifth energy level
antoniya [11.8K]

There are 9 orbitals in the third energy level and 25 orbitals in the fifth energy level.

I hope this helps you.

5 0
3 years ago
What is the source of energy for the Sun?
nikitadnepr [17]

Answer:

Nuclear fusion

Explanation:

Nuclear fusion is the source of Sun's energy.. At the core where temperature and pressure are very high hydrogen atoms fuse into helium atom and release energy in the form of Gama rays.

3 0
3 years ago
Liters of a 2.40 M
kotykmax [81]

Answer:

1.42 L

Explanation:

Step 1:

The following data were obtained from the question :

Molarity of KBr = 2.40 M

Mole of KBr = 3.40 moles

Volume of solution =?

Step 2:

Determination of the volume of the solution.

Molarity of solution is simply the mole of the solute per unit volume the of solution. It is given as :

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 3.4/2.4

Volume = 1.42 L

Therefore, the volume of the solution is 1.42 L

6 0
3 years ago
8. Neil pogo sticks from his locker to his science class. He travels 8 m east then 8 m west
jeyben [28]

Answer:

12

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5 0
3 years ago
please help me with Chem I ONLY HAVE 5 MINUTES if methane gas (CH4) flows at a rate of 0.25L/s, how many grams of methane gas wi
Nookie1986 [14]

Answer:

643g of methane will there be in the room

Explanation:

To solve this question we must, as first, find the volume of methane after 1h = 3600s. With the volume we can find the moles of methane using PV = nRT -<em>Assuming STP-</em>. With the moles and the molar mass of methane (16g/mol) we can find the mass of methane gas after 1 hour as follows:

<em>Volume Methane:</em>

3600s * (0.25L / s) = 900L Methane

<em>Moles methane:</em>

PV = nRT; PV / RT = n

<em>Where P = 1atm at STP, V is volume = 900L; R is gas constant = 0.082atmL/molK; T is absolute temperature = 273.15K at sTP</em>

Replacing:

PV / RT = n

1atm*900L / 0.082atmL/molK*273.15 = n

n = 40.18mol methane

<em>Mass methane:</em>

40.18 moles * (16g/mol) =

<h3>643g of methane will there be in the room</h3>
5 0
3 years ago
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