Answer:
88.98 %.
Explanation:
- From the balanced equation:
<em>2HCl + Pb(NO₃)₂ → 2HNO₃ + PbCl₂</em>
- It is clear that 1.0 mole of Pb(NO₃)₂ reacts with 2.0 moles of HCl to produce 1.0 mole of PbCl₂ and 2.0 moles of HNO₃.
- <em>The percent yield % of lead(II) chloride (PbCl₂) = [(actual yield) / (calculated yield)] x 100.</em>
- The actual yield of lead(II) chloride (PbCl₂) = 650 g.
- Now, we need to calculate the calculated yield of lead(II) chloride (PbCl₂).
- We need to calculate the no. of moles (n) of lead(II) nitrate (Pb(NO₃)₂) (870 grams) using the relation: <em>n = mass / molar mass.</em>
- n of lead(II) nitrate (Pb(NO₃)₂) = mass / molar mass = (870 g) / (331.2 g/mol) = 2.63 mol.
- Since HCl is in excess, the limiting reactant is lead(II) nitrate (Pb(NO₃)₂).
<u><em>Using cross multiplication:</em></u>
1.0 mole of Pb(NO₃)₂ produces → 1.0 mole of PbCl₂, from the stichiometry.
∴ 2.63 mole of Pb(NO₃)₂ produces → 2.63 mole of PbCl₂.
- The mass of PbCl₂ produced (the calculated yield) = n x molar mass = (2.63 mol) (278.1 g/mol) = 730.52 g.
∴ The percent yield % of lead(II) chloride (PbCl₂) = [(actual yield) / (calculated yield)] x 100 = [(650 g) / (730.52)] x 100 = 88.98 %.
Answer: Computational genomics (often referred to as Computational Genetics) refers to the use of computational and statistical analysis to decipher biology from genome sequences and related data, including both DNA and RNA sequence as well as other "post-genomic" data
Explanation: hope this helps
Answer:
A 03
Explanation:
jammer as verkeerd
Ek is nog steeds 'n beginner
Answer:
nosé ehhhye eee p nosé inglés
If you would’ve attached a picture I’m sure it would’ve been a lot easier.
