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Galina-37 [17]
4 years ago
5

When is a salt formed?

Chemistry
1 answer:
xxMikexx [17]4 years ago
7 0

Answer:

=> when acid reacts with base

Explanation:

In general, acid-base reactions can be represented by the following ....

acid + base => salt + weak electrolyte          

Also, you  might read the post at the Brainly link below  to better understand this topic

                     => brainly.com/question/15984607

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When a material in the liquid state is vaporized and then condensed to a liquid, the steps in the process are, respectively,?
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Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Below are the choices that can be found from other sources.
The answer is C endothermic and exothermic

<span>a. exothermic and exothermic
b. exothermic and endothermic
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3 years ago
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Which of the following reactions Shows a chemical change producing a gas? APEX
Nina [5.8K]

Answer:2CH_3OH(l)+3O_2(g)\rightarrow2CO_2(g)+4H_2O(l)

Explanation: A chemical change is a reaction in which chemical composition of the substance changes. Some bonds are broken and some new bonds are formed.

The reactants are written in terms of their chemical formula on the left hand side and the products are written in terms of their chemical formula on right hand side with a arrow in between. The chemical symbols are followed by their physical states such as (l) for liquid, (s) for solid, (g) for gas and (aq) for aqueous.

Thus the only reaction producing a gas is 2CH_3OH(l)+3O_2(g)\rightarrow2CO_2(g)+4H_2O(l)

4 0
4 years ago
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What is the freezing point of a solution in which 2.50 grams of sodium chloride are added to 230.0 ml of water
labwork [276]

The freezing point of a solution in which 2.5 grams of NaCl is added t0 230 ml of water is :  - 0.69°C

<h3>Determine the freezing point of the solution </h3>

First step : Calculate the molality of NaCl

molality =  ( 2.5 grams / 58.44 g/mol ) / ( 230 * 10⁻³ kg/ml )

              = 0.186  mol/kg

Next step : Calculate freezing point depression temperature

T = 2 * 0.186 * kf

where : kf = 1.86°c.kg/mole

Hence; T = 2 * 0.186 * 1.86 = 0.69°C

Freezing point of the solution

Freezing temperature of solvent - freezing point depression temperature

                                               0°C  -  0.69°C = - 0.69°C

Hence the Freezing temperature of the solution is  - 0.69°C

Learn more about The freezing point of a solution in which 2.5 grams of NaCl is added t0 230 ml of water is :  - 0.69°C

8 0
2 years ago
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