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2 years ago

How can the knowledge of a material’s chemical makeup or use be utilized?

Chemistry

2 answers:

shutvik [7]2 years ago

6 0

To identify minerals

Each material chemical makeup are a variety of chemical compounds which has each own category. They have different functional groups which helps people identify which material they look for. For instance, hydroxyl group has chemical makeup of alcohol

mixer [17]2 years ago

4 0

<h2>Answer:</h2>

To identify minerals

Explanation:

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100.mL of a .795 M solution of KBr is diluted to 500.mL. what is the new concentration of the solution?

kap26 [50]

Answer:

0.159 M

Explanation:

convert from mL to L then use the equation:

M1V1 = M2V2

rearrange to find M2

$\frac{M1V1}{V2} = M2$

$\frac{(0.795 M)(0.100 L)}{0.500 L} = 0.159 M$

4 0

2 years ago

2 moles of sodium chloride are dissolved in 8 liters of water. What is its molarity (M) ?

otez555 [7]

Answer:

0.25M

Explanation:

Since molarity is defined as the amount of substance in 1 liter of a solution, and amount in chemistry refers to the number of moles, molarity can be found using the equation below:

Molarity= number of moles ÷ volume in liters

Given: number of moles= 2

Volume= 8L

∴ Molarity of NaCl

= 2 ÷8

= 0.25M

4 0

3 years ago

Assume that you have a cylinder with a movable piston. What would happen to the gas pressure inside the cylinder if you do the f

pishuonlain [190]

Answer:

A. The pressure will increase 4 times. P₂ = 4 P₁

B. The pressure will decrease to half its value. P₂ = 0.5 P₁

C. The pressure will decrease to half its value. P₂ = 0.5 P₁

Explanation:

Initially, we have n₁ moles of a gas that occupy a volume V₁ at temperature T₁ and pressure P₁.

<em>What would happen to the gas pressure inside the cylinder if you do the following?</em>

<em />

<em>Part A: Decrease the volume to one-fourth the original volume while holding the temperature constant. Express your answer in terms of the variable P initial.</em>

V₂ = 0.25 V₁. According to Boyle's law,

P₁ . V₁ = P₂ . V₂

P₁ . V₁ = P₂ . 0.25 V₁

P₁ = P₂ . 0.25

P₂ = 4 P₁

<em>Part B: Reduce the Kelvin temperature to half its original value while holding the volume constant. Express your answer in terms of the variable P initial.</em>

T₂ = 0.5 T₁. According to Gay-Lussac's law,

$\frac{P_{1}}{T_{1}} =\frac{P_{2}}{T_{2}}\\\frac{P_{1}}{T_{1}} =\frac{P_{2}}{0.5T_{1}}\\\\P_{2}=0.5P_{1}$

<em>Part C: Reduce the amount of gas to half while keeping the volume and temperature constant. Express your answer in terms of the variable P initial.</em>

n₂ = 0.5 n₁.

P₁ in terms of the ideal gas equation is:

$P_{1}=\frac{n_{1}.R.T_{1}}{V_{1}}$

P₂ in terms of the ideal gas equation is:

$P_{2}=\frac{n_{2}.R.T_{1}}{V_{1}}=\frac{0.5n_{1}.R.T_{1}}{V_{1}}=0.5P_{1}$

3 0

3 years ago

Which substance can not be broken down by a chemical change

tangare [24]

Well, an element is a substance that cannot be decomposed into a simpler substance by chemical change, so element is the answer you are probably looking for! Hope this helps!

7 0

3 years ago

Liquids: A) must be contained to stay in one spot B) have a variable volume, but a fixed mass C) are usually more dense than sol

Margaret [11]

B). Have a variable volume, meaning they fill up the area they are in.

8 0

2 years ago

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