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max2010maxim [7]
3 years ago
9

The elements with 8 electrons in an outer 'd' subshell belong to Group*

Chemistry
1 answer:
Ivenika [448]3 years ago
8 0

Answer:

yftcwertyuiokjbvchff

Explanation:

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What is the movement of water up a narrow tube due to attractions with the surface of the tube called? capillary action meniscus
Shtirlitz [24]

The attraction mediated flow of water in the narrow tube has been termed as Capillary action. Thus, option A is correct.

The process of flowing up of liquid with the attraction force between the molecules and the surface has been achieved with the surface characteristics.

<h3>Movement of water in a narrow tube</h3>

The surface has the force of attraction with the flowing liquids in the sample. It results in the increased surface interaction, and the liquid flows up in the tube against gravity.

The movement of the liquid in the water through a narrow tube has been termed as capillary action. Thus, option A is correct.

Learn more about movement of water, here:

brainly.com/question/1295312

6 0
2 years ago
A sample of nitrogen gas is at a temperature of 50 c and a pressure of 2 atm. If the volume of the sample remains constant and t
Lilit [14]

Answer:

The new temperature of the nitrogen gas is 516.8 K or 243.8 C.

Explanation:

Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.

Gay-Lussac's law can be expressed mathematically as follows:

\frac{P}{T} =k

Where P = pressure, T = temperature, K = Constant

You want to study two different states, an initial state and a final state. You have a gas that is at a pressure P1 and at a temperature T1 at the beginning of the experiment. By varying the temperature to a new value T2, then the pressure will change to P2, and the following will be fulfilled:

\frac{P1}{T1} =\frac{P2}{T2}

In this case:

  • P1= 2 atm
  • T1= 50 C= 323 K (being 0 C= 273 K)
  • P2= 3.2 atm
  • T2= ?

Replacing:

\frac{2 atm}{323 K} =\frac{3.2 atm}{T2}

Solving:

T2*\frac{2 atm}{323 K} =3.2 atm

T2=3.2 atm*\frac{323 K}{2 atm}

T2= 516.8 K= 243.8 C

<u><em>The new temperature of the nitrogen gas is 516.8 K or 243.8 C.</em></u>

5 0
3 years ago
Explain how fluorine and aluminum would exchange valence electrons to form an ionic compound.
o-na [289]

Answer :

Explanation :

The aluminium and fluorine react to give ionic compound aluminium fluoride.

Aluminium has 1 valence electrons in their shell and fluorine has 7 valence electrons in their shell.

For the complete octet, both aluminium and fluorine exchange valence electrons to form an ionic compound.

The aluminium donates its three valence electrons to three fluorine atoms and they form one Al^{3+} and three F^- ions.

Electron transfer image is shown below.

5 0
3 years ago
Read 2 more answers
Help Please!!!!!!!!!!
Shkiper50 [21]

Answer:

L/EGFOU;T4444444444444444444444czgfryewi;adkb,SJJ>RL:IAO:YHSBRAGldOUSDHRIUITUER

Explanation:

DHFUIEY7RY8EFUIDJKJEUSDYRIFU8ERJFHJSX

4 0
3 years ago
If 250.0 g of water at 30.0 °C cool to 5.0 °C, how many kilojoules of energy did the water lose?
Y_Kistochka [10]

Answer:

-26.125 kj

Explanation:

Given data:

Mass of water = 250.0 g

Initial temperature = 30.0°C

Final temperature = 5.0°C

Amount of energy lost = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 5.0°C - 30.0°C

ΔT = -25°C

Specific heat of water is 4.18 j/g.°C

Now we will put the values in formula.

Q = m.c. ΔT

Q = 250.0 g × 4.18 j/g.°C × -25°C

Q = -26125 j

J to kJ

-26125 j ×1 kj /1000 j

-26.125 kj

5 0
3 years ago
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