The attraction mediated flow of water in the narrow tube has been termed as Capillary action. Thus, option A is correct.
The process of flowing up of liquid with the attraction force between the molecules and the surface has been achieved with the surface characteristics.
<h3>Movement of water in a narrow tube</h3>
The surface has the force of attraction with the flowing liquids in the sample. It results in the increased surface interaction, and the liquid flows up in the tube against gravity.
The movement of the liquid in the water through a narrow tube has been termed as capillary action. Thus, option A is correct.
Learn more about movement of water, here:
brainly.com/question/1295312
Answer:
The new temperature of the nitrogen gas is 516.8 K or 243.8 C.
Explanation:
Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.
Gay-Lussac's law can be expressed mathematically as follows:
Where P = pressure, T = temperature, K = Constant
You want to study two different states, an initial state and a final state. You have a gas that is at a pressure P1 and at a temperature T1 at the beginning of the experiment. By varying the temperature to a new value T2, then the pressure will change to P2, and the following will be fulfilled:

In this case:
- P1= 2 atm
- T1= 50 C= 323 K (being 0 C= 273 K)
- P2= 3.2 atm
- T2= ?
Replacing:

Solving:


T2= 516.8 K= 243.8 C
<u><em>The new temperature of the nitrogen gas is 516.8 K or 243.8 C.</em></u>
Answer :
Explanation :
The aluminium and fluorine react to give ionic compound aluminium fluoride.
Aluminium has 1 valence electrons in their shell and fluorine has 7 valence electrons in their shell.
For the complete octet, both aluminium and fluorine exchange valence electrons to form an ionic compound.
The aluminium donates its three valence electrons to three fluorine atoms and they form one
and three
ions.
Electron transfer image is shown below.
Answer:
L/EGFOU;T4444444444444444444444czgfryewi;adkb,SJJ>RL:IAO:YHSBRAGldOUSDHRIUITUER
Explanation:
DHFUIEY7RY8EFUIDJKJEUSDYRIFU8ERJFHJSX
Answer:
-26.125 kj
Explanation:
Given data:
Mass of water = 250.0 g
Initial temperature = 30.0°C
Final temperature = 5.0°C
Amount of energy lost = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 5.0°C - 30.0°C
ΔT = -25°C
Specific heat of water is 4.18 j/g.°C
Now we will put the values in formula.
Q = m.c. ΔT
Q = 250.0 g × 4.18 j/g.°C × -25°C
Q = -26125 j
J to kJ
-26125 j ×1 kj /1000 j
-26.125 kj