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3 years ago

How many moles of oxygen are in 8.24 moles Mg(NO3)2

Chemistry

1 answer:

malfutka [58]3 years ago

5 0

Answer:

49.4 mol Oxygen

Explanation:

Mg(NO3)2 ----- 6 O

1 mol 6 mol

8.24 mol x mol

x = 8.24*6/1 = 49.44 mol ≈ 49.4 mol Oxygen

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The black, granular material that fills a dry cell in a common flashlight (between the carbon rod and the zinc shell) is mangane

mestny [16]

Answer: c. +4

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

$Mn:25:1s^22s^22p^63s^23p^64s^23d^{5}$

$Mn^{4+}:21:1s^22s^22p^63s^23p^63d^1$

$O:8:1s^22s^22p^4$

$O^{2-}:10:1s^22s^22p^6$

Here manganese is having an oxidation state of +4 called as cation and oxygen forms an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged to give $Mn_2O_4$ which written in simplest whole number ratios to give neutral $MnO_2$

7 0

3 years ago

The amount of a chemical solution is measured to be 2 liters.

irinina [24]

2 liters may be 1.5 to 1.9 rounded up to 2 or 2.1 or 2.4 rounded down to 2.

2 - 1.5 = 0.5

percent error = (absolute error / quantity) * 100

percent error = 0.5/2 * 100% = 0.25 * 100% = 25%

Choice C. 25%.

3 0

3 years ago

Given the following unbalanced equation:

antiseptic1488 [7]

<h3>Answer:</h3>

11.84 mol CoF₂

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Moles

<u>Stoichiometry</u>

Using Dimensional Analysis
Analyzing Reactions RxN

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Unbalanced] CoCl₂ + F₂ → CoF₂ + Cl₂

[RxN - Balanced] CoCl₂ + F₂ → CoF₂ + Cl₂

[Given] 11.84 moles CoCl₂

[Solve] moles CoF₂

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol CoCl₂ → 1 mol CoF₂

<u>Step 3: Stoich</u>

[DA] Set up: $\displaystyle 11.84 \ mol \ CoCl_2(\frac{1 \ mol \ CoF_2}{1 \ mol \ CoCl_2})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 11.84 \ mol \ CoF_2$