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Yuliya22 [10]
3 years ago
5

I need help with number 7 and 8. Gravity is 10N NOT 9.8N for these problems

Physics
1 answer:
noname [10]3 years ago
8 0
7A 8A maybe I’m not sure sorry if it’s wrong.
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Voltage needed to raise current to 3.75a using 20,20,200 resistor set
Varvara68 [4.7K]

<u>Answer:</u> The voltage needed is 35.7 V

<u>Explanation:</u>

Assuming that the resistors are arranged in parallel combination.

For the resistors arranged in parallel combination:

\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}

We are given:

R_1=20\Omega\\R_2=20\Omega\\R_3=200\Omega

Using above equation, we get:

\frac{1}{R}=\frac{1}{20}+\frac{1}{20}+\frac{1}{200}\\\\\frac{1}{R}=\frac{10+10+1}{200}\\\\R=\frac{200}{21}=9.52\Omega

Calculating the voltage by using Ohm's law:

V=IR         .....(1)

where,

V = voltage applied

I = Current = 3.75 A

R = Resistance = 9.52\Omega

Putting values in equation 1, we get:

V=3.75\times 9.52\\\\V=35.7V

Hence, the voltage needed is 35.7 V

7 0
3 years ago
Read 2 more answers
A block of mass 9.5kg rests on a slope an angle of 23.0∘ relative to the horizontal. What is the size of the contact force norma
Rudiy27

The Normal Force = M x G x Cos(theta)

= 9.5 Kg x 9.8 m/s^2 x cos 23

= 9.5 Kg x 9.8 m/s^2 x 0.9205

Converting Kg to Newton,

1 Kg  = 9.81 N

= 9.5 Kg x 9.81 N x 9.8 m/s^2 x 0.9205

= 840.702 N

6 0
3 years ago
A solid sphere of diameter D = 26 cm has a charge of Q = 4 nano-coulombs uniformly distributed on it. Calculate the magnitude of
kozerog [31]

Answer:

E = 4.83  N/ C

Explanation:

If we have a uniform charge sphere we can use the following formulas to calculate the Electric field due to the charge of the sphere:

E= \frac{k*Q}{r^{2} } : Formula (1) To calculate the electric field in the region outside the sphere r ≥ a

Where:

K: coulomb constant (N*m²/C²)

a: sphere radius (m)

Q:  Total sphere charge (C)

r : Distance from the center of the sphere to the region where the electric field is calculated (m)

Equivalences

1nC=10⁻⁹C

1cm= 10⁻²m

Data

k= 9*10⁹ N*m²/C²

Q=4nC=4 *10⁻⁹C

D = 26 cm = 26*10⁻²m = 0.26m

a = D/2 = 0.13m

r= R+a = 2.6 m+ 0.13m = 2.73m

Problem development

Magnitude of the electric field at r = 2.73m from the center of the sphere  

r>a , We apply the Formula (1) :

E= \frac{k*Q}{r^{2} }

E= \frac{9*10^{9}*4*10^{-9} }{2.73^{2} }

E= 4.83 N/ C

3 0
3 years ago
3. Predict which of the following ions would be likely to form: _____ a. Na2+ _____ b. Cl+ _____ c. Ca2+ _____ d. Br– _____ e. N
Over [174]
The answer is : <span> Ca2+ & </span><span> Br. 
Na2 would not give away 2 electrons.
Cl would not give away any electron
Ne- & Ne+ are noble gases, so, they do not give up or take electrons.</span>
6 0
3 years ago
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An object has a mass of 48g and a volume of 6cm cubed (like a little 3 above the m) Calculate the density of this object
jonny [76]

       Density  =  (mass) / (volume)

                    =  (48 g)  /  (6 cm³)
 
                    =  (48 / 6)  (g / cm³)

                    =          8 g/cm³ 
                    
5 0
4 years ago
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