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Valentin [98]
3 years ago
14

Brandon works at a small petting zoo with 8 animals he was looking at some data showing the masses of the animals each animal ha

d a different mass between two and 160 kg the zoo then buys a horse that weighs 900 kg as their ninth animal how does buying a horse affect mean and median

Mathematics
1 answer:
Minchanka [31]3 years ago
3 0

Answer:

B

Step-by-step explanation:

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G(n)=-4n+2; find g(8)<br>​
yarga [219]

Answer:

-30

Step-by-step explanation:

In g(8) the 8 = n.  So, substitute 8 in for n in the expression -4n + 2

g(8)  =  -4(8) + 2 = -32 + 2 = -30

4 0
3 years ago
Read 2 more answers
Is 0.007x10 equivalent to 0.07
djverab [1.8K]

Answer: yes.

Step-by-step explanation:

adding 10 is moving the decimal point once to the right, so yes.

move the decimal point in 0.007 once to the right (multiply it by 10) and you get 0.07

5 0
3 years ago
Read 2 more answers
Find the product. (r s)2 r² 2rs s r² 2rs s² r² 2rs 2s².
sveta [45]

The product of the given expression is \rm 2r^3+ s^3r^3+ 2r^3s + sr^3+ 2s^3+ 6rs.

Given

The product of \rm 2r^2(r + s) + 2rs + s^2 + 2rs + s^2r^2+ 2rs + 2s^2.

<h3>What is multiplication?</h3>

Multiplication is the process of calculating the product of two or more numbers.

The multiplication of numbers say, ‘a’ and ‘b’, is stated as ‘a’ multiplied by ‘b’.

The product of \rm 2r^2(r + s) + 2rs + s^2 + 2rs + s^2r^2+ 2rs + 2s^2 is given by;

\rm 2r^2(r + s) + 2rs + s^2 + 2rs + s^2r^2+ 2rs + 2s^2\\\\(2r^3 + 2r^2s) + 2rs + 2rs + 2rs + s^2r^2 + sr^2 + 2s^2\\\\2r^3+ 2r^2s + 6rs + s^2r^2 + sr^2+ 2s^2

\rm 2r^3+ s^3r^3+ 2r^3s + sr^3+ 2s^3+ 6rs

Hence, the product of the given expression is \rm 2r^3+ s^3r^3+ 2r^3s + sr^3+ 2s^3+ 6rs.

To know more about Multiplication click the link given below.

brainly.com/question/19943359

6 0
2 years ago
Subtract rational expression. <br> Show work please.
yan [13]

Given:

$\frac{x+4}{x-1}-\frac{5}{x^{2}-1}

To find:

The simplified rational expression by subtraction.

Solution:

Let us factor x^2-1. It can be written as x^2-1^2.

x^2-1^2=(x-1)(x+1) using algebraic identity.

$\frac{x+4}{x-1}-\frac{5}{x^{2}-1}=\frac{x+4}{x-1}-\frac{5}{(x+1)(x-1)}

LCM of x-1,(x+1)(x-1)=(x+1)(x-1)

Make the denominators same using LCM.

Multiply and divide the first term by (x + 1) to make the denominator same.

                        $=\frac{(x+4)(x+1)}{(x-1)(x+1)}-\frac{5}{(x-1)(x+1)}

Now, denominators are same, you can subtract the fractions.

                        $=\frac{(x+4)(x+1)-5}{(x-1)(x+1)}

Expand (x+4)(x+1)-5.

                        $=\frac{x^2+4x+x+4-5}{(x-1)(x+1)}

                        $=\frac{x^{2}+5 x-1}{(x-1)(x+1)}

$\frac{x+4}{x-1}-\frac{5}{x^{2}-1}=\frac{x^{2}+5 x-1}{(x-1)(x+1)}

6 0
3 years ago
Solve for x (9x-16°)=3x+11°
meriva
X = 9/2 have a nice day
6 0
3 years ago
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