What is the area of triangle ABC?

Mathematics

2 answers:

pashok25 [27]3 years ago

5 0

Answer:

B) Area of triangle = 56 cm².

Step-by-step explanation:

Given : A isosceles triangle with sides 12 cm and 14cm , 12 cm and also height is 8cm.

To find : Area of triangle.

Solution: We have given that

Isosceles triangle with same sides 12 cm.

Base of triangle = 14 cm .

Height = 8 cm.

Area of triangle = $\frac{1}{2} * base * height$ .

Plugging the values

Area of triangle = $\frac{1}{2} * 14 * 8$ .

Area of triangle = 7 *8 = 56 cm².

Therefore, B) Area of triangle = 56 cm².

solmaris [256]3 years ago

4 0

Area of triangle = 1/2 x base x height.
Base = 14 cm
Height = 8 cm
Area = 1/2 x 8 x 14 = 56 cm^2

Correct option B

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Rylee read 36 pages of a book before putting

asambeis [7]

Answer:

D. 12p + 36 > 480

Step-by-step explanation:

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2 years ago

Find the area and perimeter of the room.. the vertices are 10,20 -10,20 -10,-10 10,-10

Ierofanga [76]

The numbers in this problem are ordered pairs, which are points on a graph.
These are (10, 20), (-10, 20), (-10, -10), and (10, -10).
To find the area and perimeter of this shape, you must first find the distance between each point.

Distance between (10, 20) and (-10, 20):
Since the y-value remains the same here, we just have to find the difference in x-values.
This means 10 - (-10)
A negative being subtracted is the same as a positive being added.
That means 10 - (-10) is the same as 10 + 10.
10 + 10 = 20, so the distance between (10, 20) and (-10, 20) is 20 units.

Distance between (-10, 20) and (-10, -10):
The x-values are the same here so just find the difference between the y-values.
20 - (-10) = 20 + 10 = 30
The distance between the (-10, 20) and (-10, -10) is 30 units.

Distance between (-10, -10) and (10, -10):
The y-values are the same so just find the difference between the x-values.
10 - (-10) = 10 + 10 = 20
The distance between (-10, -10) and (10, -10) is 20 units.

Distance between (10, -10) and (10, 20):
The x-values are the same so find the difference between the y-values.
20 - (-10) = 20 + 10 = 30
The distance between (10, -10) and (10, 20) is 30 units.

So now we know the side lengths of the room are 20 units, 30 units, 20 units, and 30 units.

To find the perimeter, add all the side lengths together.
20 + 30 + 20 + 30 = 100
The perimeter of the room is 100 units.

To find the area, multiply the length by the width.
The length is 20 units and the width is 30 units.
20 • 30 = 600
The area of the room is 600 units.

Final answers:
Perimeter = 100
Area = 600

Hope this helps!

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3 years ago

PLEASE HELP I WILL GIVE BRAINLIEST!!!!! I already solved for x please solve for y and z! Trolls are getting reported and banned

hoa [83]

Not sure if your the same person but I had already done the work for this problem....