Question

Two players play the following game. Player A chooses one of three spinners. Spinner 1 has 3 regions numbered 9,5 and 1, Spinner 2 has three regions numbered 3,8 and 4, and Spinner 3 has three regions numbered 7,6 and 2. Player B then chooses one of the two remaining spinners. Both players spin their spinner and the one that lands on the higher number is declared the winner. Assuming that each spinner is equally likely to land in any of its 3 regions, would you rather be player A or player B?

Answer 1

Answer:

Hence, player A will win with probability = 5/9. Explanation has given below.

Step-by-step explanation:

Two player such as A and B chose the three spinners and contain numbered 9 , 5 and 1.

Spinner one has 3 regions = (9, 5, 1)

Spinner 2 has three regions= (3, 8, 4)

Spinner 3 has three regions = (7, 6, 2)

Let

Player A chooses one of three spinners = (9, 5, 1)

Player B chose spinner = (3, 8, 4)

Possible outcomes are = [ (9,3), (9,8), (9,4), (5,3), (5,8), (5,4), (1,3), (1,8), (1,4)]

Total possible outcomes are = 9

One with the higher number wins the game.

Player A wins = (9,3), (9,8), (9,4), (5,3), (5, 4)

Player B wins = (5, 8), (1,3), (1,8), (1,4)

Hence, player A will win with probability = 5/9.